Question

18,54, 162, ... Find the 8th term.

Answer 1

Answer:

a₈ = 39366

Step-by-step explanation:

The terms have a common ratio between consecutive terms

r = 54 ÷ 18 = 162 ÷ 54 = 3

This indicates the sequence is geometric with nth term

$a_{n}$ = a₁ $(r)^{n-1}$

where a₁ is the first term and r the common ratio

Here a₁ = 18 and r = 3 , then

a₈ = 18 × $3^{7}$ = 18 × 2187 = 39366