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Komok [63]
3 years ago
11

What is the answer to this?

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
6 0

Answer:

C

Step-by-step explanation:

Neither linear nor exponentional make sense.

Hope this helps!!! XD

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The volume of a sphere can be described by the following formula, where V = volume and r = radius of the sphere.
Anika [276]

Option C: r = \sqrt[3]{\frac{3V}{4\pi} } is the right answer

Step-by-step explanation:

Given formula for volume of a sphere is:

V = \frac{4}{3}\pi r^3

We have to make r the subject of the formula

Multiplying equation by 3/4

\frac{3}{4}V = \frac{4}{3} * \frac{3}{4} \pi r^3\\\frac{3}{4}V = \pi r^3

Dividing both sides by pi

\frac{3}{4\pi}V =\frac{ \pi r^3}{\pi}\\\frac{3V}{4\pi} = r^3

Taking cube root on both sides

\sqrt[3]{\frac{3V}{4\pi} } = \sqrt[3]{r^3} \\ r = \sqrt[3]{\frac{3V}{4\pi} }

Hence,

Option C: r = \sqrt[3]{\frac{3V}{4\pi} } is the right answer

Keywords: Volume, Sphere

Learn more about volume at:

  • brainly.com/question/12973601
  • brainly.com/question/13063819

#LearnwithBrainly

5 0
3 years ago
Which fraction is equivalent to 1/2 • 4/3 divided by 5/6 ?
Katen [24]

I believe the answer you are looking for is 4/5.

Solution:

1/2 • 4/3=2/3

2/3÷5/6=2/3 • 6/5

4/5

5 0
2 years ago
Find the work done by F= (x^2+y)i + (y^2+x)j +(ze^z)k over the following path from (4,0,0) to (4,0,4)
babunello [35]

\vec F(x,y,z)=(x^2+y)\,\vec\imath+(y^2+x)\,\vec\jmath+ze^z\,\vec k

We want to find f(x,y,z) such that \nabla f=\vec F. This means

\dfrac{\partial f}{\partial x}=x^2+y

\dfrac{\partial f}{\partial y}=y^2+x

\dfrac{\partial f}{\partial z}=ze^z

Integrating both sides of the latter equation with respect to z tells us

f(x,y,z)=e^z(z-1)+g(x,y)

and differentiating with respect to x gives

x^2+y=\dfrac{\partial g}{\partial x}

Integrating both sides with respect to x gives

g(x,y)=\dfrac{x^3}3+xy+h(y)

Then

f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+h(y)

and differentiating both sides with respect to y gives

y^2+x=x+\dfrac{\mathrm dh}{\mathrm dy}\implies\dfrac{\mathrm dh}{\mathrm dy}=y^2\implies h(y)=\dfrac{y^3}3+C

So the scalar potential function is

\boxed{f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+\dfrac{y^3}3+C}

By the fundamental theorem of calculus, the work done by \vec F along any path depends only on the endpoints of that path. In particular, the work done over the line segment (call it L) in part (a) is

\displaystyle\int_L\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(4,0,0)=\boxed{1+3e^4}

and \vec F does the same amount of work over both of the other paths.

In part (b), I don't know what is meant by "df/dt for F"...

In part (c), you're asked to find the work over the 2 parts (call them L_1 and L_2) of the given path. Using the fundamental theorem makes this trivial:

\displaystyle\int_{L_1}\vec F\cdot\mathrm d\vec r=f(0,0,0)-f(4,0,0)=-\frac{64}3

\displaystyle\int_{L_2}\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(0,0,0)=\frac{67}3+3e^4

8 0
3 years ago
How do you do ratio charts
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Write several instances of the ratio,then plot the ratios as points on the graph
8 0
3 years ago
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7-C=4<br><br><br> Hint: equation and rational coefficient
nalin [4]

Answer:

you stupid and dumb person

5 0
3 years ago
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