Answer:
x²/2166784 +y²/2159989 = 1
Step-by-step explanation:
The relationship between the semi-axes and the eccentricity of an ellipse is ...
e = √(1 -b²/a²)
In order to write the desired equation we need to find 'b' from 'e' and 'a'.
__
<h3>semi-minor axis</h3>
Squaring the equation for eccentricity gives ...
e² = 1 -b²/a²
Solving for b², we have ...
b²/a² = 1 -e²
b² = a²(1 -e²)
<h3>ellipse equation</h3>
Using the given values, we find ...
b² = 1472²(1 -0.056²) = 2166784(0.996864) ≈ 2159989
The desired equation is ...
x²/2166784 +y²/2159989 = 1
Find the domain of
y = log(x + 3)
Logarithms can only be taken for positive numbers. So you must have
x + 3 > 0
x > – 3 ✔
So the domain of the function is
D = {x ∈ R: x > – 3}
or using the interval notation
D = (– 3, +∞)
I hope this helps. =)
The measure of each exterior angle is 60° and the polygon has 6 sides ⇒ 4th answer
Step-by-step explanation:
In a regular n-side polygon:
- All sides are equal in lengths
- All angles are equal in measure
- The measure of each interior angle =
- The measure of each exterior angle =
- The sum of interior angle and exterior angle at a vertex is 180°
∵ The measure of an interior angle of a regular polygon is 120°
∵ The sum of interior angle and exterior angle at a vertex = 180°
∴ The measure of each exterior angle = 180 - 120
∴ The measure of each exterior angle = 60°
∵ The measure of each exterior angle =
- Substitute the measure of the exterior angle by 60
∴ 
- By using cross multiplication
∴ 60 n = 360
- Divide both sides by 60
∴ n = 6
∴ The polygon has 6 sides
The measure of each exterior angle is 60° and the polygon has 6 sides
Learn more:
You can learn more about polygons in brainly.com/question/6281564
#LearnwithBrainly
Answer:
61.25%
Step-by-step explanation:
How many ml of 20 percent acid should be added to pure acid
to make 70 ml of 30 percent acid?
:
let x = amt of 20% mixture
then
(70-x) = amt of pure acid
:
0.20x + (70-x) =0 .30(70)
0.20x + 70 - x = 21
= 21 - 70
-0.8x =-49
x = 61.25%
x = +61.25 ml of 20% stuff
That’s a lot of words i don’t know
