Answer:
<u>Use cross-multiplication to solve these</u>
- 1) 6/2 = 4/p ⇒ 6p = 4*2 ⇒ p = 8/6 ⇒ p = 4/3
- 2) 4/k = 8/2 ⇒ 8k = 2*4 ⇒ k = 8/8 ⇒ k = 1
- 3) n/4 = 8/7 ⇒ n = 4*8/7 ⇒ n = 32/7
- 4) 5/3 = x/4 ⇒ x = 4*5/3 ⇒ x = 20/3
Answer:12
Step-by-step explanation: first you replace w for 16 and divide that by 4 because of GEMDAS or PEMDAS.. Your left with 4 now add 4 plus 8 which is 12
If you meant that 1 ball can complete a full rotation in 120 mins then to have a 180 min rotation you need 1.5 balls.
Answer:
true
Step-by-step explanation:
<span>A 0.176 times 10 to the power of 18 km =
</span><span><span>A 176.0 times 10^15 km
</span>B 22.13 times 10 to the
power of 16 km =
2.213 x 10^15 km
C 31.42 times 10 to the power of 14 km =
3.142 x 10^15 km
D 125.5
times 10 to the power of 15 km
</span>
The recalculated list is now:
<span>A 176.0 times 10^15 km
</span>
<span>B 2.213 x 10^15 km
</span><span>C 3.142 x 10^15 km
</span>
<span>D 125.5 x 10^15 km
</span>
Just by looking, we can see the 2 stars closest to each other are
<span>C 3.142 x 10^15 km and
</span><span>B 2.213 x 10^15 km
The distance between them = </span>3.142 x 10^15 km -<span>2.213 x 10^15 km
.929 x 10^15 km =
9.29 x 10^14 km
</span>