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Tanzania [10]
3 years ago
8

A miner for gold digs at a constant rate. They were able to dig -90 feet in 6 hours. How long have they been digging if they dug

-225 feet?
Mathematics
1 answer:
Pachacha [2.7K]3 years ago
7 0

Answer:

he will dig for 15 hours

Step-by-step explanation:

if a miner digs —90 feets in 6 hours

then he will dig –225 feet in x hours

—225 feet x 6 hours /—90 feet = 15 hours

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Please help<br> Picture inserted <br> Multiple choice <br> Will appreciate it if u help!
Ksenya-84 [330]

Answer: B) Linear; it can be written as y = -3x-6

We subtract 6 from both sides to go from the original equation to -3x-6 = y

Then we flip both sides to end up with y = -3x-6

This is in slope intercept form y = mx+b with m = -3 as the slope and b = -6 as the y intercept.

4 0
3 years ago
33. What is the value of x when x + 10 = 4?<br> A. -14<br> B. -6<br> C. O<br> D. 6
SCORPION-xisa [38]

Answer:

B. -6

Step-by-step explanation:

-6 + 10 =4

7 0
3 years ago
Read 2 more answers
Express the -0.345 in the form of p\q and reduce it to the lowest term​
Mamont248 [21]

Answer:

-69/200

Step-by-step explanation:

-0.345 is in decimal form.

In Fractional form (p/q)

=-345/1000

To simplify, divide the numerator and the denominator by the G.C.D(Greatest Common Divisor) of p and q.

In this case,G.C.D of 345 and 1000 is 5.

Simplified form=-69/200 [ANS]

3 0
3 years ago
Let f(x)=3x+2 and g(x)=5x-8 find all value of x for which f(x) &gt; g(x)
kirill115 [55]

Answer:

x < 5

Step-by-step explanation:

f(x)  > g(x) \\    <  =  > 3x + 2 > 5x + 2 \\  <  =  >  - 2x >  - 10 \\   <  =  > x < 5  \:( qed)

4 0
3 years ago
Dos cuadrados de lado
Kaylis [27]

La franja amarilla del rectángulo tiene un área de 30 centímetros cuadrados.

<h3>¿Cuál es el área de la franja amarilla del rectángulo?</h3>

En este problema tenemos un rectángulo formado por dos cuadrados que se traslapan uno al otro. La franja amarilla es el área en la que los cuadrados se traslapan. La anchura del rectángulo es descrita por la siguiente ecuación:

(10 - x) + 2 · x = 17

Donde x se mide en centímetros.

A continuación, despejamos x en la ecuación descrita:

10 + x = 17

x = 7

Ahora, el área de la franja amarilla se determina mediante la fórmula de area de un rectángulo:

A = b · h

Donde:

  • b - Base del rectángulo, en centímetros.
  • h - Altura del rectángulo, en centímetros.
  • A - Área del rectángulo, en centímetros cuadrados.

A = (10 - 7) · 10

A = 3 · 10

A = 30

El área de la franja amarilla del rectángulo es igual a 30 centímetros cuadrados.

Para aprender más sobre áreas de rectángulos: brainly.com/question/23058403

#SPJ1

8 0
1 year ago
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