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Tanzania [10]
3 years ago
8

A miner for gold digs at a constant rate. They were able to dig -90 feet in 6 hours. How long have they been digging if they dug

-225 feet?
Mathematics
1 answer:
Pachacha [2.7K]3 years ago
7 0

Answer:

he will dig for 15 hours

Step-by-step explanation:

if a miner digs —90 feets in 6 hours

then he will dig –225 feet in x hours

—225 feet x 6 hours /—90 feet = 15 hours

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Ashley is making $500 a week at her job. She receives a 20% pay raise.
tamaranim1 [39]

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What is the sum of the first 70 consecutive odd numbers? Explain.
expeople1 [14]

The sum of the first n odd numbers is n squared! So, the short answer is that the sum of the first 70 odd numbers is 70 squared, i.e. 4900.

Allow me to prove the result: odd numbers come in the form 2n-1, because 2n is always even, and the number immediately before an even number is always odd.

So, if we sum the first N odd numbers, we have

\displaystyle \sum_{i=1}^N 2i-1 = 2\sum_{i=1}^N i - \sum_{i=1}^N 1

The first sum is the sum of all integers from 1 to N, which is N(N+1)/2. We want twice this sum, so we have

\displaystyle 2\sum_{i=1}^N i = 2\cdot\dfrac{N(N+1)}{2}=N(N+1)

The second sum is simply the sum of N ones:

\underbrace{1+1+1\ldots+1}_{N\text{ times}}=N

So, the final result is

\displaystyle \sum_{i=1}^N 2i-1 = 2\sum_{i=1}^N i - \sum_{i=1}^N 1 = N(N+1)-N = N^2+N-N = N^2

which ends the proof.

5 0
2 years ago
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