Ask question

Ask question

All categories

pickupchik [31]

2 years ago

11

Please help!!!! Middle school math

2 answers:

kifflom [539]2 years ago

8 0

Answer:

2,728‬ words

Step-by-step explanation:

So this is a basic multiplication problem, so we just multiply the only numbers there:

88 x 31 = 2,728‬

So Captain's Sea Stories has 2,728‬ words in total

hope this helps:)

mamaluj [8]2 years ago

6 0

Answer:

about 2728 words

Step-by-step explanation:

Just multiply the number of words per page by the total number of pages in the book

w=words

p=pages

w * p =?

88 * 31 = ?

88 * 31 = 2728

You might be interested in

What's the answer?<br> Idk it bc I'm stupid and I don't feel like doing it

aliya0001 [1]

H=-16x to the second power +136

4 0

3 years ago

In class, 5/9 of the students have blue Eyes. if 10 students have blue eyes, how many students are in the class in total?

KiRa [710]

Let us cross multiply.

5/9=10/x

9 x 10= 5x

90=5x

90 <u />÷ 5= 5x <span>÷ 5

18=x

So, the answer is 18. I hope this helped you, since I just learned cross multiplication last week.</span>

8 0

2 years ago

Read 2 more answers

Plz help me I have no idea how to do this

Leviafan [203]

Answer:

0.8

Step-by-step explanation:

cos z = 8/10 = 0.8

8 0

3 years ago

Convert this decimal to a simplified fraction:<br><br> 0.32

alexdok [17]

The answer is 8/25
Hope it helped

3 0

2 years ago

Read 2 more answers

Find the perimeter of WXYZ. Round to the nearest tenth if necessary.

yanalaym [24]

Answer:

C. 15.6

Step-by-step explanation:

Perimeter of WXYZ = WX + XY + YZ + ZW

Use the distance formula, $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$ to calculate the length of each segment.

✔️Distance between W(-1, 1) and X(1, 2):

Let,

$W(-1, 1) = (x_1, y_1)$

$X(1, 2) = (x_2, y_2)$

Plug in the values

$WX = \sqrt{(1 - (-1))^2 + (2 - 1)^2}$

$WX = \sqrt{(2)^2 + (1)^2}$

$WX = \sqrt{4 + 1}$

$WX = \sqrt{5}$

$WX = 2.24$

✔️Distance between X(1, 2) and Y(2, -4)

Let,

$X(1, 2) = (x_1, y_1)$

$Y(2, -4) = (x_2, y_2)$

Plug in the values

$XY = \sqrt{(2 - 1)^2 + (-4 - 2)^2}$

$XY = \sqrt{(1)^2 + (-6)^2}$

$XY = \sqrt{1 + 36}$

$XY = \sqrt{37}$

$XY = 6.08$

✔️Distance between Y(2, -4) and Z(-2, -1)

Let,

$Y(2, -4) = (x_1, y_1)$

$Z(-2, -1) = (x_2, y_2)$

Plug in the values

$YZ = \sqrt{(-2 - 2)^2 + (-1 -(-4))^2}$

$YZ = \sqrt{(-4)^2 + (3)^2}$

$YZ = \sqrt{16 + 9}$

$YZ = \sqrt{25}$

$YZ = 5$

✔️Distance between Z(-2, -1) and W(-1, 1)

Let,

$Z(-2, -1) = (x_1, y_1)$

$W(-1, 1) = (x_2, y_2)$

Plug in the values

$ZW = \sqrt{(-1 -(-2))^2 + (1 - (-1))^2}$

$ZW = \sqrt{(1)^2 + (2)^2}$

$ZW = \sqrt{1 + 4}$

$ZW = \sqrt{5}$

$ZW = 2.24$

✅Perimeter = 2.24 + 6.08 + 5 + 2.24 = 15.56

≈ 15.6

5 0

3 years ago