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2 years ago

What is the range of a function f(x)=-x+15 when the domain is {-3,-1,11}?

Mathematics

1 answer:

hodyreva [135]2 years ago

4 0

Answer:

The range is the output value or the y value.

You would work backwards to find the domain.

f(x) = 4x - 1 f(x) = 4x - 1

3 = 4x - 1 7 = 4x - 1

add 1 to both sides add 1 to both sides

4 = 4x 8 = 4x

divide both sides by 4 divide both sides by 4

x = 1 x = 2

f(x) = 4x - 1 f(x) = 4x - 1

11 = 4x - 1 15 = 4x - 1

add 1 to both sides add 1 to both sides

12 = 4x 16 = 4x

divide both sides by 4 divide both sides by 4

x = 3 x = 4

Domain { 1, 2, 3, 4}

Step-by-step explanation:

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7nadin3 [17]

Answer:

never

Step-by-step explanation:

5 degrees above zero is never a negative, it's positive

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2 years ago

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leonid [27]

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Step-by-step explanation:

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2 years ago

Tara has 3 over 4 cup of ice cream. How many 1 over 5 -cup servings are in 3 over 4 cup of ice cream?

qwelly [4]

Answer:

0.15 cup servings

Step-by-step explanation:

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8 0

3 years ago

Tony wants to save $10,000 in 6 years. Assuming a 4% interest rate, what is the minimum he must save each month to reach his goa

arlik [135]

We have been given that Tony wants to save $10000 in 6 years.

That means future value S = $10000

Time t= 6 years

Interest rate = 4% yearly = 0.04 yearly

n=12 months per year

Now we have to find monthly payment to recieve $10000 in 6 years. so we need to apply monthly payment formula which is

$S=R(\frac{(1+\frac{r}{n})^{nt}-1}{\frac{r}{n}})$

$10000=R(\frac{(1+\frac{0.04}{12})^{12*6}-1}{\frac{0.04}{12}})$

$10000=R(\frac{(1+0.00333333333333)^{72}-1}{0.00333333333333})$

$10000=R(\frac{(1.00333333333333)^{72}-1}{0.00333333333333})$

$10000=R(\frac{1.27074187908-1}{0.00333333333333})$

$10000=R(\frac{0.27074187908}{0.00333333333333})$

$10000=R(81.2225637241)$

$\frac{10000}{81.2225637241}=R$

$123.11849739=R$

which is approx $123.

Hence final answer is C) $123.

4 0

3 years ago

Write the expression in complete factored form<br><br> 4u^2(a-3)+q(a-3)

Sauron [17]

[ Answer ]

$\boxed{\bold{4au^{2} \ - \ 12u^{2} \ + \ aq \ - \ 3q}}$

[ Explanation ]

Factor: $4u^{2}$ (a - 3) + q(a - 3)

-------------------------------------

Expand $4u^2\left(a-3\right)$ : $4au^2-12u^2$

$4au^2-12u^2+q\left(a-3\right)$

Expand

$q\left(a-3\right)$ : $aq-3q$

Answer

$4au^2-12u^2+aq-3q$

$\boxed{\bold{[] \ Eclipsed \ []}}$

3 0

2 years ago