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3 years ago

What is the range of a function f(x)=-x+15 when the domain is {-3,-1,11}?

Mathematics

1 answer:

hodyreva [135]3 years ago

4 0

Answer:

The range is the output value or the y value.

You would work backwards to find the domain.

f(x) = 4x - 1 f(x) = 4x - 1

3 = 4x - 1 7 = 4x - 1

add 1 to both sides add 1 to both sides

4 = 4x 8 = 4x

divide both sides by 4 divide both sides by 4

x = 1 x = 2

f(x) = 4x - 1 f(x) = 4x - 1

11 = 4x - 1 15 = 4x - 1

add 1 to both sides add 1 to both sides

12 = 4x 16 = 4x

divide both sides by 4 divide both sides by 4

x = 3 x = 4

Domain { 1, 2, 3, 4}

Step-by-step explanation:

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Charles and Seth are building a ramp for Sasha and Samantha. The base of the triangle is 11ft and it's height is 5ft. How long i

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Step-by-step explanation:

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3 years ago

An open box with a square base is to be made from a square piece of cardboard 24 inches on a side by cutting out a square from e

laila [671]

Answer:

x=4 Inch

Step-by-step explanation:

Length of the Square = 24 Inches

If a Square of Length x cm is cut out from each corner

Length of the Box = 24-x-x=(24-2x) Inches

Width of the Box =24-x-x=(24-2x) Inches

Height of the box = x inches

Volume of a Cuboid = Length X Width X Height

V(x)= x(24-2x)(24-2x)

Simplifying

V(x)=4x(12-x)(12-x)

To determine the value of x at which V is largest, we take the derivative of V(x) and solve for the critical points.

V(x)=4x(12-x)(12-x)

$V^{'}(x)=12(x-12)(x-4)$

Set the derivative equal to zero to obtain the critical points

$V^{'}(x)=12(x-12)(x-4)=0\\Since \: 12\neq 0\\(x-12)(x-4)=0\\x-12=0 \:or\: x-4=0\\x=12 \:or\: x=4$

x cannot be equal to 12 as it divides the length of the square cardboard into exactly two equal parts.

When x=4

V(4)=4*4(12-4)(12-4)=16*8*8=1024 Cubic Inches

When x=4 Inch, the volume, V of the open box is largest.

3 0

3 years ago

Evaluate using the order of operation 3/4+5/6÷2/3

Novosadov [1.4K]

3/4+5/6 divided by 2/3 is 8/4 or 2
Do 5/6 divided by 2/3 first to get 5/4
then use 5/4 to +3/4 and the answer is 8/4 or 2

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