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Finger [1]
3 years ago
6

Is 2/6 rational or irrational

Mathematics
2 answers:
Margarita [4]3 years ago
6 0
I think it’s rational because irrational can be written as a decimal, but NOT as a fraction
Zanzabum3 years ago
3 0

Answer:

Rational

Step-by-step explanation:

A rational number is any integer, fraction, terminating decimal, or repeating decimal.

<em>good luck, i hope this helps :) </em>

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128x³y⁴-56x²y²-72x⁴y² by 16x²y
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Step-by-step explanation:

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3 0
2 years ago
The length of a rectangle is measured as 370mm correct to 2 significant figures.
olga nikolaevna [1]

Answer:

UB: 375

Step-by-step explanation:

370mm to 2 sig figs..

UB: 375

LB:365

Please rate me 5 stars and thank me :)

5 0
3 years ago
Solve the system by using a matrix equation (Picture provided)
Katyanochek1 [597]

Answer:

Option b is correct (8,13).

Step-by-step explanation:

7x - 4y = 4

10x - 6y =2

it can be represented in matrix form as\left[\begin{array}{cc}7&-4\\10&-6\end{array}\right] \left[\begin{array}{c}x\\y\end{array}\right] = \left[\begin{array}{c}4\\2\end{array}\right]

A= \left[\begin{array}{cc}7&-4\\10&-6\end{array}\right]

X= \left[\begin{array}{c}x\\y\end{array}\right]

B= \left[\begin{array}{c}4\\2\end{array}\right]

i.e, AX=B

or X= A⁻¹ B

A⁻¹ = 1/|A| * Adj A

determinant of A = |A|= (7*-6) - (-4*10)

                                    = (-42)-(-40)

                                    = (-42) + 40 = -2

so, |A| = -2

Adj A=  \left[\begin{array}{cc}-6&4\\-10&7\end{array}\right]

A⁻¹ =  \left[\begin{array}{cc}-6&4\\-10&7\end{array}\right]/ -2

A⁻¹ =  \left[\begin{array}{cc}3&-2\\5&-7/2\end{array}\right]

X= A⁻¹ B

X=  \left[\begin{array}{cc}3&-2\\5&-7/2\end{array}\right] *\left[\begin{array}{c}4\\2\end{array}\right]

X= \left[\begin{array}{c}(3*4) + (-2*2)\\(5*4) + (-7/2*2)\end{array}\right]

X= \left[\begin{array}{c}12-4\\20-7\end{array}\right]

X= \left[\begin{array}{c}8\\13\end{array}\right]

x= 8, y= 13

solution set= (8,13).

Option b is correct.

3 0
3 years ago
1. P(x)=x^2+2<br> 2. P(x)= 2x +10
ruslelena [56]

Answer:

see explanation

Step-by-step explanation:

Since p(x) = x² + 2 , if x ≤ 4

For x = 4 then this is included in the inequality x ≤ 4

whereas x > 4 does not include x = 4 but values greater than 4

Thus to evaluate x = 4 use p(x) = x² + 2

4 0
3 years ago
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