Answer:
1) The series of equations that can be used to find the numbers are
7·x + 3·y = 54...(1)
x = y + 2...(2)
2) The first number is 6
The second number is 4
Step-by-step explanation:
1) The given parameters for the numbers are;
7 times the first number + 3 times the 2nd number = 54
The first number = The 2nd number + 2
Let 'x' represent the first number and let 'y' represent the second number
The following series of equations can therefore be used in finding the numbers;
7·x + 3·y = 54...(1)
x = y + 2...(2)
2) By substituting the value of x = y + 2 from equation (2) into equation (1) gives;
7·x + 3·y = 54
∴ 7×(y + 2) + 3·y = 54
7·y + 14 + 3·y = 54
10·y + 14 = 54
10·y = 54 - 14 = 40
y = 40/10 = 4
The second number = y = 4
The first number, x = y + 2 = 4 + 2 = 6
The first number, x = 6.
