Answer:
P(A U B)= 0.08
Step-by-step explanation:
1.Let:
P(A) as the probability that a psiton has an under-fill defect
P(B) as the probability that a pistón has a porosity defect
P(A ∩ B) the probability of having both defectos
Then:
P(A)=0.05
P(B)=0.04
P(A ∩ B)=0.01
2. The probability that a randomly chosen piston has a defect could be calcularse as the union of the probability of choosing a piston with am under-fill defect and one with porosity defect.
That Is P(A U B)
Aplying the probability properties we have:
P(A U B)= P(A) + P(B) -P(A ∩ B)
Replacing the probabilities:
P(A U B)= 0.05+0.04-0.01
P(A U B)= 0.08
Answer:
163.3
Step-by-step explanation:
3.14*r^2*h
h=13
4/2 = 2
r=2
2^2 = 4
3.14*4 = 12.56
12.56*13 = 163.28
Rounded = 163.3
I believe the answer is 163.3
Answer:
24x+93
That's the answer to the equation that was what you were asking for right?
