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3 years ago

If f(x) =-2x+9 and g(x)=-4x^2+5x-3 ,find (f•g)(x)

Mathematics

1 answer:

madam [21]3 years ago

4 0

Answer:

f(x)=-2x+9 g(x)=-4x^2+5x-3Now, f o g (x) = f{g(x)} = f(4x^2+5x-3) = 2(4x^2+5x-3) + 9 = 8x^2+10x-6 + 9

Step-by-step explanation:

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ElenaW [278]

Answer with Step-by-step explanation:

We are given that

$f(x)=\left\{\begin{matrix}\dfrac{x^2-2x}{x^2-4}&,if\ \ x\neq 2 \\ 1&,if\ \ x=2\end{matrix}\right.$

We have to explain that why the function is discontinuous at x=2

We know that if function is continuous at x=a then LHL=RHL=f(a).

$f(x)=\frac{x(x-2)}{(x+2)(x-2)}=\frac{x}{x+2}$

LHL=Left hand limit when x <2

Substitute x=2-h

where h is small positive value >0

$\lim_{h\rightarrow 0}f(x)=\lim_{h\rightarrow 0}\frac{2-h}{2-h+2}$

$\lim_{h\rightarrow 0}\frac{2-h}{4-h}=\frac{2}{4}=\frac{1}{2}$

Right hand limit =RHL when x> 2

Substitute

x=2+h

$\lim_{h\rightarrow 0}f(x)=\lim_{h\rightarrow 0}\frac{2+h}{2+h+2}=\lim_{h\rightarrow 0}\frac{2+h}{4+h}$

$=\frac{2}{4}=\frac{1}{2}$

LHL=RHL= $\frac{1}{2}$

f(2)=1

$LHL=RHL\neq f(2)$

Hence, function is discontinuous at x=2

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4 years ago

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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