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3 years ago

There were 300 adults and 180 children at a football game. What percent of the spectators were adults?

Mathematics

1 answer:

kotykmax [81]3 years ago

7 0

Answer:

62.5

Step-by-step explanation:

300+180=480

300/480×100

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PLEASE NEED HELP QUESTION AND ANSWERS IN THE PIC

guajiro [1.7K]

Answer:

Step-by-step explanation:

CDE and CBA are similar triangles

Ratio = CE/CA = 24/48 = 1/2

CD/CB = 1/2

18/(24+x) = 1/2

24+x = 36

x = 12

DE/BA = 1/2

y/24 = 1/2

y = 12

6 0

3 years ago

Help!!

sveticcg [70]

The surface are of the right cone is 176 sq.units. Option A) is the correct answer.

Step-by-step explanation:

step 1 :

Radius of the cone, r = 4

Height or length of the cone, h = 10

step 2 :

Total surface area of right cone = πrh + πr^2

= (π $\times$ 4 $\times$ 10) + ( π $\times$ 4^2)

= 40π + 16π

= 56 π = 56 $\times$ 3.14

= 176 sq.units

5 0

3 years ago

Decrease $7500 by 7% please help i need step by step explanation

soldier1979 [14.2K]

(100% - 7%) × 7,500

= 93% × 7,500

= 93 ÷ 100 × 7,500

= 93 × 7,500 ÷ 100

= 697,500 ÷ 100

= 6975
hope this helped

6 0

3 years ago

Read 2 more answers

A gas is said to be compressed adiabatically if there is no gain or loss of heat. When such a gas is diatomic (has two atoms per

Tems11 [23]

Answer:

The pressure is changing at $\frac{dP}{dt}=3.68$

Step-by-step explanation:

Suppose we have two quantities, which are connected to each other and both changing with time. A related rate problem is a problem in which we know the rate of change of one of the quantities and want to find the rate of change of the other quantity.

We know that the volume is decreasing at the rate of $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ and we want to find at what rate is the pressure changing.

The equation that model this situation is

$PV^{1.4}=k$

Differentiate both sides with respect to time t.

$\frac{d}{dt}(PV^{1.4})= \frac{d}{dt}k\\$

The Product rule tells us how to differentiate expressions that are the product of two other, more basic, expressions:

$\frac{d}{{dx}}\left( {f\left( x \right)g\left( x \right)} \right) = f\left( x \right)\frac{d}{{dx}}g\left( x \right) + \frac{d}{{dx}}f\left( x \right)g\left( x \right)$

Apply this rule to our expression we get

$V^{1.4}\cdot \frac{dP}{dt}+1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}=0$

Solve for $\frac{dP}{dt}$

$V^{1.4}\cdot \frac{dP}{dt}=-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}\\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}}{V^{1.4}} \\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}$

when P = 23 kg/cm2, V = 35 cm3, and $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ this becomes

$\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}\\\\\frac{dP}{dt}=\frac{-1.4\cdot 23 \cdot -4}{35}}\\\\\frac{dP}{dt}=3.68$

The pressure is changing at $\frac{dP}{dt}=3.68$ .

7 0

4 years ago

-12x divided by -4= -27 what does x equal

Ede4ka [16]

X=9 -12 divided by -4 is -3, so you get -3x=-27. When you divide -27 by -3 you get positive 9. Thus making X=9

7 0

4 years ago