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Ivanshal [37]
3 years ago
13

Is 3.13 greater than 3.12

Mathematics
2 answers:
kkurt [141]3 years ago
7 0

Answer:

Yes

Step-by-step explanation:

13 is greater than 12 so

3.13>3.12

hoped this helped... :)

katen-ka-za [31]3 years ago
3 0

Answer:

yes

Step-by-step explanation:

if we figure out the difference between the two numbers by subtracting one from the other, if the product comes out positive, then the number you subtracted from is greater, if the product comes up negative, then the number you subtracted from is lesser

say we did 3.13 as our first number

3.13 - 3.12 = 0.01

this means that 3.13 is greater by 0.01, if we switch the two numbers however...

3.12 - 3.13 = -0.01

then that means that 3.12 is lesser by 0.01

i hope this makes sence, working with decimals may get tricky sometimes lol

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Here is your answer

0= x+3

Add -3 to both sides,

-3= x+3-3

-3= x

So,

x=-3

HOPE IT IS USEFUL

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Two forces with magnitudes of 100 and 50 pounds act on an object at angles of 50° and 160°, respectively. Find the direction and
MatroZZZ [7]
<h2>Hello!</h2>

Since there is no additional information, we can assume that the given angles are respect to the horizontal axis (x), so

The answer is:

Magnitude: 95.14 lbs

Direction: 80° respect to the x-axis

<h2>Why?</h2>

Since there is no additional information about the given angles, we can assume that both angles are respect to the horizontal axis (x), positive direction to x-axis positive directions (right) and above x-axis.

<h2>Calculations:</h2>

100 pounds (lb) force, 50° angle:

100lbs*cos(50)=64.28lbs\\100lbs*sin(50)=76.60lbs

50 pounds (lb) force, 160° angle:

50lbs*cos(160)=-46.98lbs\\50lbs*sin(160)=17.10lbs

So,

For x-axis forces we have:

64.28lbs (positive direction)

-46.98lbs (negative direction)

Then,

64.28lbs-46.98lbs=17.3lbs (positive direction)

Fox y-axis forces we have:

76.60lbs (positive direction)

17.10 lbs (positive direction)

Then,

76.60lbs + 17.10 lbs =93.7lbs (positive direction)

So, we have the two components values of the acting force:

17.3 lbs for the x-axis and 93.7 lbs for the y-axis.

Therefore,

We have to calculate the angle between both resultant force components:

Let's calll it α

So,

\alpha=tan^{-1}(\frac{y-axisValue}{x-axisValue})=tan^{-1}(\frac{93.7}{17.3})\\\alpha=79.5=80

Hence, the angle between both resultant force components is 80 °, meaning that the resultant force direction is positive, above the x-axis.

Now we have to calculate the magnitude of the resultant force since the sum of both resultant force components is equal to the hypotenuse of the formed triangle, we have that:

sin(\alpha)=\frac{y-axisValue}{ResultantForceMagnitude}=\frac{93.7lbs}{ResultantForceMagnitude}\\\\ResultantForceMagnitude=\frac{93.7lbs}{sin(80)}=95.14lbs

So, we have that:

  • Resultant force magnitude is equal to 95.14 lbs
  • Direction is 80° respect to the x-axis.

Have a nice day!

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