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IceJOKER [234]
2 years ago
5

I need help please please

Mathematics
1 answer:
damaskus [11]2 years ago
8 0
Here’s the correct answer, how I got it, and something to help you for next time. I know it’s a lot of words but if u read the explanation it might help you :)

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What is the perimeter of the trapezoid with vertices Q(8, 8), R(14, 16), S(20, 16), and T(22, 8)? Round to the nearest hundredth
EleoNora [17]
Check the picture below.

so... you can pretty much see how long RS and QT are, you can just count the units off the grid.

now, let's find QR's length

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&Q&(~ 8 &,& 8~) 
%  (c,d)
&R&(~ 14 &,& 16~)
\end{array}~~ 
%  distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
QR=\sqrt{(14-8)^2+(16-8)^2}\implies QR=\sqrt{6^2+8^2}
\\\\\\
QR=\sqrt{36+64}\implies QR=\sqrt{100}\implies QR=10

and let's also find the length for ST

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&S&(~ 20 &,& 16~) 
%  (c,d)
&T&(~ 22 &,& 8~)
\end{array}~ 
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
ST=\sqrt{(22-20)^2+(8-16)^2}\implies ST=\sqrt{2^2+(-8)^2}
\\\\\\
ST=\sqrt{4+64}\implies ST=\sqrt{68}\implies ST=\sqrt{4\cdot 17}
\\\\\\
ST=\sqrt{2^2\cdot 17}\implies ST=2\sqrt{17}

so, add the lengths of all sides, and that's the perimeter of the trapezoid.

8 0
3 years ago
Read 2 more answers
Course challenge
krek1111 [17]

Answer:

x=36

Divide the corresponding side (16) by 4/7

3 0
1 year ago
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Find X (Its a circle question, PLEASE HELP) ​
mario62 [17]

Step-by-step explanation:

Since angles in the same segment are equal, Angle ABC (x) = Angle AOC.

Since Angles AOC and COD are supplementary, Angle AOC = 180° - 130° = 50°

Therefore x = 50°.

7 0
3 years ago
How do I solve this properly?
o-na [289]

Answer:

x \geq 4

Step-by-step explanation:

4x^2 - 64 \geq 0 ; move 64 over

4x^2 \geq 64 ; divide by 4

x^2 \geq 16 ; take square root of both sides

x \geq 4

6 0
3 years ago
Consider the equations y = |x − 1| and y = 3x + 2.
Dima020 [189]
(-0.2,1.2)

substitute 3x+2 for y and set them equal to eachother then plug in x for y
5 0
3 years ago
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