23. Assuming the green is flat, what is the radius of the green?
1 answer:
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Answer:
B)blocks in 5th row=15+(5-1)(-2)
Step-by-step explanation:
We are given that
Number of block in bottom row=15
Each row has 2 fewer blocks than the previous row
We have to find the formula would you use to find the number of blocks in the 5th row.
Number of blocks in second row=15-2=
Number of blocks in third row=15-2-2=
Number of blocks in 4th row=
Number of blocks in 5th row=
Therefore, number of block in 5th row
This is required formula to find the number of blocks in the 5th row
Hence, option B is true.
B)blocks in 5th row=15+(5-1)(-2)
gallon = pint *0.125
gallon = pint / 8
0.125+0.125+0.125+0.125+0.125+0.125+0.125+0.125+0.125+0.125+0.125+
0.125+0.125+0.125+0.125+0.125 = 2
16 would be the answer I believe, maybe I'm wrong, double check.
Answer:
a. The test statistic for this hypothesis would be z=1.71
b. Critical value at α = 0.10: z=1.282
c. Reject H0, the television network should not keep its current lineup.
d. H0: p ≤ 0.50; HA: p > 0.50
Step-by-step explanation:
We have to performa an hypothesis test on a proportion.
The claim is that the proportion of viewers that prefer the new show is bigger than 50% (meaning that most viewers prefer the new show).
The null hypothesis will state that both shows have the same proportion.
Then, the null and alternative hypothesis are:
The sample proportion is p=0.53
The standard error of the proportion is:
Then, the z-statistic can be calculated as:
The critical value for a right tailed test at a significance level of 0.10 is zc=1.282. This value can be looked up in a standard normal distribution table.
As the statistic is bigger than the critical value, it lies in the rejection region. The null hypothesis is rejected. There is evidence to support the claim that the proportion of viewers which support the new show is larger than 0.50.