Answer:
4x
Step-by-step explanation:
The Taylor series of a function f(x) about a value x = a is given by f(x) = f(a) + f'(a)(x - a)/1! + f''(a)(x - a)²/2! + f'''(a)(x - a)³/3! + ... where the terms in f prime f'(a) represent the derivatives of x valued at a.
For the given function, f(x) = 4x and a = -2
So, f(a) = f(-2) = 4(-2) = -8
f'(a) = f'(-2) = 4
All the higher derivatives of f(x) evaluated at a are equal to zero. That is f''(a) = f'"(a) =...= 0
Substituting the values of a = -2, f(a) = f(-2) = -8 and f'(-2) = 4 into the Taylor series, we have
f(x) = f(-2) + f'(-2)(x - (-2))/1! + f''(-2)(x - (-2))²/2! + f'''(-2)(x - (-2))³/3! +...
= -8 + 4(x + 2)/1! + (0)(x + 2)²/2! + (0)(x + 2)³/3! +...
= -8 + 4(x + 2) + 0 + 0
= -8 + 4x + 8
= 4x
Answer:
A = - 2n - 1
Step-by-step explanation:
A=-3+(n-1)(-2)
<=> A = - 3 - 2(n-1)
<=> A = - 3 - 2n -2×(-1)
<=> A = - 3 - 2n + 2
<=> A = - 1 - 2n = - 2n - 1
Answer:
x = 16
Step-by-step explanation:
m<B+m<C+m<D = 180°
5x + 14 + x + 19 + 2x + 19 = 180
8x + 52 = 180
8x = 180 - 52
x = 128/8
x = 16
Answer:
a. 53.68
b. 53.53
Step-by-step explanation:
a. Step 1: Approximate the value for :
Since is close to (which is 8), this value can be approximated as a number that is less than but very close to 8. I chose 7.9.
The expression becomes 6(7.9)+2π
Step 2: Approximate the value for 2π
Since π is approximately 3.14, 2π is approximately 6.28.
The expression becomes 6(7.9)+6.28
Step 3: Use order of operations
6(7.9)+6.28=47.4+6.28=53.68
b. Step 4: If allowed, use a calculator to check how close your approximation is to the actual value
The approximation 53.68 is decently close to the actual value, so no minor math errors were made.
Answer:
B1=2 B2=5
Step-by-step explanation: