Answer:
3
Step-by-step explanation:
The product of 3.99 and 3.3 will have 3 decimals.
When multiplying decimals, you add the decimals to get the total number of decimals in your product.
2+1=3 so it will have 3 decimals.
So here, you just put in the value inside the parenthesis of the function into the actual function itself.
Here, for h(f(2)), the first one to put in is the one in f, which is 2.
Since f(x) = 3*2^x, and since x here is equal to 2, (because h(f(2)), we can just put in the 2 in place of the x.
3 * 2 ^ 2
And then you get:
3 * 4
Or 12.
So now you have
h(12)
Now do the same thing.
2 * 12 - 7
24 - 7
17
Answer:
The product of 8x(5x−6) is 40x^2−48x
The product of (x−3)(5x−6) is 5x^2−21x+18
Step-by-step explanation:
<u><em>Verify each option</em></u>
Part 1) The product of 8x(5x−6) is 40x^2−48x
we have

Applying distributive property

Compare with the given value

therefore
The statement is true
Part 2) The product of −4x(2x2+1) is −8x^3−5x
we have

Applying distributive property

Compare with the given value

therefore
The statement is not true
Part 3) The product of (x−3)(5x−6) is 5x^2−21x+18
we have

Applying distributive property

Compare with the given value

therefore
The statement is true
Part 4) The product of (2x+3)(x^2+3x−5) is 2x^3+9x^2+9x−25
we have

Applying distributive property

Compare with the given value

therefore
The statement is not true
Answer: $
Step-by-step explanation:
Question: $36.60 with the discount of 20%?
Steps:
Discount = Original Price * Discount %100
Discount =
× 
Discount =
× 
You save = $
Final Price = Original Price - Discount
Final Price = 
Final Price = $
~I hope I helped :)~
Answer:
dy/dt = - (1/5) ft/s = - 0.2 ft/s
Step-by-step explanation:
Given
L = 5 ft
Qin = 25 ft³/s
Qout = 30 ft³/s
h = 10 ft
dy/dt = ?
We can apply the relation
ΔQ = Qint - Qout = 25 ft³/s - 30 ft³/s
⇒ ΔQ = - 5 ft³/s
Then we use the formula
Q = v*A
where Q = ΔQ, A = L² is the area of square base and v = dy/dt is the rate of change in the depth of the solution in the tank
⇒ ΔQ = (dy/dt)*L²
⇒ dy/dt = ΔQ/L²
⇒ dy/dt = (- 5 ft³/s)/(5 ft)²
⇒ dy/dt = - (1/5) ft/s = - 0.2 ft/s