Six times a number increased by 20 is four less than eight times the number. Find the number
1 answer:
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Answer:
(D) Divide the first equation, , by 2.
Step-by-step explanation:
Given:
We need to find the operation performed on equation so as to get resultant equation as:
From Above we can see that there is no change in equation 2 with respect to resultant equation.
Also Resultant equation is simplified form of equation 1.
Simplifying equation 1 we get;
We can see that 2 is the common multiple on both side.
Hence we will divide equation 1 with 2 we get
which is the resultant equation.
Hence (D) Divide the first equation, , by 2 is the correct option.
In can be less mental effort if the equation is multiplied by -1 first.
.. x^2 -10x +8 = 0
.. x^2 -10x +25 +8 -25 = 0
.. (x -5)^2 = 17
.. x -5 = ±√17
.. x = 5 ±√17
The values of x that satisfy the given equation are
.. x = 5 -√17 ≈ 0.877
.. x = 5 +√17 ≈ 9.123
.. x^2 -10x +8 = 0
.. x^2 -10x +25 +8 -25 = 0
.. (x -5)^2 = 17
.. x -5 = ±√17
.. x = 5 ±√17
The values of x that satisfy the given equation are
.. x = 5 -√17 ≈ 0.877
.. x = 5 +√17 ≈ 9.123