Six times a number increased by 20 is four less than eight times the number. Find the number

1 answer:

4 0

Greetings!

"<span>Six times a number increased by 20 is four less than eight times the number. Find the number."...

This would be, as an equation:
</span> $6x+20=8x-4$

Solve:
Add 4 and -6x to both sides.
$(6x+20)+4+(-6x)=(8x-4)+4+(-6x)$
Simplify.
$24=2x$
Divide both sides by 2.
$(24)/2=(2x)/2$
Simplify.
$12=x$
$x=12$
<span>
x=12

Hope this helps.
-Benjamin

</span>

You might be interested in

Ryan obtains a loan for home renovations from a bank that charges simple interest at an annual rate of 9.65%. His loan is for $1

Mila [183]

well, with the assumption that a year has 365 days, that means one day is really just 1/365th of a year, so then 54 days will be 54/365 of a year.

$~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\dotfill & \$17100\\ r=rate\to 9.65\%\to \frac{9.65}{100}\dotfill &0.0965\\ t=years\dotfill &\frac{54}{365} \end{cases} \\\\\\ I = (17100)(0.0965)(\frac{54}{365})\implies \stackrel{\textit{interest owed}}{I\approx 244.13}~\hfill \underset{amount~owed}{\stackrel{17100~~ + ~~244.13}{\approx 17344.13}}$