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Viefleur [7K]
3 years ago
7

Six times a number increased by 20 is four less than eight times the number. Find the number

Mathematics
1 answer:
DaniilM [7]3 years ago
4 0
Greetings!

"<span>Six times a number increased by 20 is four less than eight times the number. Find the number."...

This would be, as an equation:
</span>6x+20=8x-4

Solve:
Add 4 and -6x to both sides.
(6x+20)+4+(-6x)=(8x-4)+4+(-6x)
Simplify.
24=2x
Divide both sides by 2.
(24)/2=(2x)/2
Simplify.
12=x
x=12
<span>
x=12

Hope this helps.
-Benjamin

</span>
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Answer:

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Step-by-step explanation:

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Answer:

The ship S is at 10.05 km to coastguard P, and 12.70 km to coastguard Q.

Step-by-step explanation:

Let the distance of the ship to coastguard P be represented by x, and its distance to coastguard Q be represented by y.

But,

<P = 048°

<Q = 360^{o} - 324^{o}

     = 036^{o}

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<P + <Q + <S = 180^{o}

048° + 036^{o} + <S = 180^{o}

84^{o} + <S = 180^{o}

<S  = 180^{o} -  84^{o}

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Applying the Sine rule,

\frac{y}{Sin P} = \frac{x}{Sin Q} = \frac{z}{Sin S}

\frac{y}{Sin P} = \frac{z}{Sin S}

\frac{y}{Sin 48^{o} } = \frac{17}{Sin 96^{o} }

\frac{y}{0.74314} = \frac{17}{0.99452}

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\frac{x}{Sin 36^{o} } = \frac{17}{Sin 96^{o} }

\frac{x}{0.58779} = \frac{17}{0.99452}

⇒ x = \frac{9.992430}{0.99452}

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x = 10.05 km

Thus,

the ship S is at a distance of 10.05 km to coastguard P, and 12.70 km to coastguard Q.

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