The slope of a line that passes through each pair of points (2,2), (3,1) is (4,2), (0,2)
In a trapezoid, two opposite sides are parallel and are called bases.
In this trapezoid, the top and bottom sides are parallel and are the bases.
The right side that intersects both bases is a transversal.
When parallel lines are cut by a transversal, same-side interior angles are supplementary. The measures of supplementary angles add to 180 deg.
x + 72 = 180
x = 180 - 72
x = 108 deg
Answer:
2A) The centre is (-3,2) and the radius is 5.
Step-by-step explanation:
2A)
Okay so if you have the equation of a circle in standard from (ie it looks something like this: (x-h)² + (y-k)² = r² ), it's pretty easy to find the centre and radius because in this form, r is the radius and (h,k) is the centre of the circle.
Note that (x-h)² + (y-k)² = x²+(-2h)x+h² + y²+(-2k)y+k²
In our case [x²+y²+6x-4y-12=0], we can see that -2h=6 (because 6 is the coefficient of x) and -2k=-4 (because -4 is the coefficient of y).
-2h=6, h=-3
-2k=-4, k=2
Let's sub these in:
x²+(-2h)x+h² + y²+(-2k)y+k² = r²
x²+6x+(-3)² + y²-4y+(2)² = r²
x²+6x+9 + y²-4y+4 = r²
x²+y²+6x-4y+(13-r²)=0
x²+y²+6x-4y+(13-r²)=x²+y²+6x-4y-12=0
13-r²=-12
r²=25
r=5
So our equation in standard form is (x+3)²+(y-2)²=25, which means the centre is (-3,2) and the radius is 5.
Answer:
2/3 is the correct answer so C. Hope this helps you. :)
Step-by-step explanation: