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astraxan [27]
2 years ago
13

2 divided by negative 1/5

Mathematics
1 answer:
oksian1 [2.3K]2 years ago
4 0

Answer: 10

you have to find a common denominator between two and five which is 10. therefore making the number 2 into the fraction 20/10 and finding the common denominator of 1/5 makes it now 2/10. now divide 20 by 2 which gets you 10. and dividing 10 by 10 gets you. therefore making the new fraction 10/1 which is equal to 10. :)

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Triangle abc is an isosceles right triangle. What is the measure of one base angle? 30ş 45ş 60ş 90ş.
alisha [4.7K]

Answer:

  45°

Step-by-step explanation:

The acute angles of a right triangle are complementary. The base angles of an isosceles triangle are congruent. If x is the measure of the base angles, this requires ...

  x = 90-x . . . . . the base angle is congruent to the other base angle

  2x = 90 . . . . . add x

  x = 90/2 = 45 . . . . divide by 2

The measure of a base angle of an isosceles right triangle is 45°.

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It can be useful to remember this fact.

5 0
2 years ago
Katie says ‘when you half a whole number that ends in 6, you always get a number that ends in 3.’ Write down an example to prove
mart [117]

Answer:

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6 0
3 years ago
Help fill in the blanks plz
Nady [450]

Answer:

a=(c+2b)/5

Step-by-step explanation:

Like terms in one side to subject a.

When exchanging sides make sure u do inverse operations. Therefore;

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a = (c+2b)/5

3 0
3 years ago
What is the following sum? 2 (RootIndex 3 StartRoot 16 x cubed y EndRoot) 4 (RootIndex 3 StartRoot 54 x Superscript 6 Baseline y
san4es73 [151]

Equivalent expressions are expressions that have the same value, and can be used interchangeably.

The result of the sum 2 (\sqrt[3]{16x^3y})  + 4 (\sqrt[3]{54x^6y^5}) is 4x\sqrt[3]{2y}  + 8x^2y\sqrt[3]{2y^2})

The expression is given as:

2 (\sqrt[3]{16x^3y})  + 4 (\sqrt[3]{54x^6y^5})

Rewrite the expression as:

2 (\sqrt[3]{16x^3y})  + 4 (\sqrt[3]{54x^6y^5}) = 2 (\sqrt[3]{2^4x^3y})  + 4 (\sqrt[3]{3^3 \times 2x^6y^5})

Evaluate the roots

2 (\sqrt[3]{16x^3y})  + 4 (\sqrt[3]{54x^6y^5}) = 2 (2x\sqrt[3]{2y})  + 4 (3x^2y\sqrt[3]{2y^2})

Open the brackets

2 (\sqrt[3]{16x^3y})  + 4 (\sqrt[3]{54x^6y^5}) = 4x\sqrt[3]{2y}  + 12x^2y\sqrt[3]{2y^2})

The above expression cannot be further simplified.

Hence, the result of the sum 2 (\sqrt[3]{16x^3y})  + 4 (\sqrt[3]{54x^6y^5}) is 4x\sqrt[3]{2y}  + 8x^2y\sqrt[3]{2y^2})

Read more about equivalent expressions at:

brainly.com/question/2972832

7 0
2 years ago
Read 2 more answers
What is 15% of $24.00?
NARA [144]
(.15)(24)= $3.6 That would be the answer
8 0
3 years ago
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