Answer:
45°
Step-by-step explanation:
The acute angles of a right triangle are complementary. The base angles of an isosceles triangle are congruent. If x is the measure of the base angles, this requires ...
x = 90-x . . . . . the base angle is congruent to the other base angle
2x = 90 . . . . . add x
x = 90/2 = 45 . . . . divide by 2
The measure of a base angle of an isosceles right triangle is 45°.
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It can be useful to remember this fact.
Answer:
a=(c+2b)/5
Step-by-step explanation:
Like terms in one side to subject a.
When exchanging sides make sure u do inverse operations. Therefore;
9a - 4a = c + 2b
5a = c + 2b
a = (c+2b)/5
Equivalent expressions are expressions that have the same value, and can be used interchangeably.
The result of the sum
is ![4x\sqrt[3]{2y} + 8x^2y\sqrt[3]{2y^2})](https://tex.z-dn.net/?f=4x%5Csqrt%5B3%5D%7B2y%7D%20%20%2B%208x%5E2y%5Csqrt%5B3%5D%7B2y%5E2%7D%29)
The expression is given as:
![2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5})](https://tex.z-dn.net/?f=2%20%28%5Csqrt%5B3%5D%7B16x%5E3y%7D%29%20%20%2B%204%20%28%5Csqrt%5B3%5D%7B54x%5E6y%5E5%7D%29)
Rewrite the expression as:
![2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5}) = 2 (\sqrt[3]{2^4x^3y}) + 4 (\sqrt[3]{3^3 \times 2x^6y^5})](https://tex.z-dn.net/?f=2%20%28%5Csqrt%5B3%5D%7B16x%5E3y%7D%29%20%20%2B%204%20%28%5Csqrt%5B3%5D%7B54x%5E6y%5E5%7D%29%20%3D%202%20%28%5Csqrt%5B3%5D%7B2%5E4x%5E3y%7D%29%20%20%2B%204%20%28%5Csqrt%5B3%5D%7B3%5E3%20%5Ctimes%202x%5E6y%5E5%7D%29)
Evaluate the roots
![2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5}) = 2 (2x\sqrt[3]{2y}) + 4 (3x^2y\sqrt[3]{2y^2})](https://tex.z-dn.net/?f=2%20%28%5Csqrt%5B3%5D%7B16x%5E3y%7D%29%20%20%2B%204%20%28%5Csqrt%5B3%5D%7B54x%5E6y%5E5%7D%29%20%3D%202%20%282x%5Csqrt%5B3%5D%7B2y%7D%29%20%20%2B%204%20%283x%5E2y%5Csqrt%5B3%5D%7B2y%5E2%7D%29)
Open the brackets
![2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5}) = 4x\sqrt[3]{2y} + 12x^2y\sqrt[3]{2y^2})](https://tex.z-dn.net/?f=2%20%28%5Csqrt%5B3%5D%7B16x%5E3y%7D%29%20%20%2B%204%20%28%5Csqrt%5B3%5D%7B54x%5E6y%5E5%7D%29%20%3D%204x%5Csqrt%5B3%5D%7B2y%7D%20%20%2B%2012x%5E2y%5Csqrt%5B3%5D%7B2y%5E2%7D%29)
The above expression cannot be further simplified.
Hence, the result of the sum
is ![4x\sqrt[3]{2y} + 8x^2y\sqrt[3]{2y^2})](https://tex.z-dn.net/?f=4x%5Csqrt%5B3%5D%7B2y%7D%20%20%2B%208x%5E2y%5Csqrt%5B3%5D%7B2y%5E2%7D%29)
Read more about equivalent expressions at:
brainly.com/question/2972832
(.15)(24)= $3.6 That would be the answer