So the formula you need for this is
A=1/2bh
So count the squares on the outside of the bottom of the triangle and the left so that would be 7 and 7 so you multiply those together to get 49 then you would divide that answer by 2 and get 24.5 so your answer is 24.5 :)
Yes, it is better to switch your choice.
At first, you had a 1/3 chance of wining a car.
Then the professor eliminated an option.
Now you are left with either a goat or a car.
Now instead of having a 1/3 chance, you have a 1/2 chance of selecting the car.
This is famous for the Monty Hall Problem: https://www.youtube.com/watch?v=mhlc7peGlGg
Please see the pic, I'd solved in it.
Answer:
0.0918 = 9.18% probability that a randomly selected male has a height > 180 cm.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 170cm and standard deviation of 7.5 cm.
This means that ![\mu = 170, \sigma = 7.5](https://tex.z-dn.net/?f=%5Cmu%20%3D%20170%2C%20%5Csigma%20%3D%207.5)
Find the probability that a randomly selected male has a height > 180 cm.
This is 1 subtracted by the pvalue of Z when X = 180. So
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{180 - 170}{7.5}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B180%20-%20170%7D%7B7.5%7D)
![Z = 1.33](https://tex.z-dn.net/?f=Z%20%3D%201.33)
has a pvalue of 0.9082
1 - 0.9082 = 0.0918
0.0918 = 9.18% probability that a randomly selected male has a height > 180 cm.
I’m not sure if your answer is right but here’s how to solve it