Answer:
7
Step-by-step explanation:
The formula for intersecting chords creating which create the limits of arcs and associated angles is
<HES = 1/2 (ARC HS + ARC GF)
<HES = 1/2 (ARC 51 + ARC 195)
<HES = 1/2 (246)
<HES = 123
What that tells you is that <GEF = the same thing because <HES and <GEF are vertically opposite.
Now I am going to assume that <HES = 16x + 11. This is not a sure thing, but I assume it is what is intended.
16x + 11 = 123 Subtract 11 from both sides
16x = 123 - 11
16x = 112 Divide by 16
x = 112/16
x = 7
Break the problem into two parts: 1) the area of the this isosceles triangle whose hypotenuse is AB and 2) the area of the semicircle whose diameter is AB.
The triangle is isosceles because the lengths of the two shorter legs are the same (2 meters). Use the Pythagorean Theorem to find the length of the hypotenuse of this triangle. (AB)^2 = (2 m)^2 + (2 m)^2, or 8 m^2. Thus, AB = sqrt(8 m^2), or 2sqrt(2). This AB is also the base of the triangle. What is the area of the triangle?
Next, noting that the diameter AB of the semicircle is 2sqrt(2) and the radius is just sqrt(2), find the area of the semicircle. The area of a circle of radius r
is pi*r^2; here it's pi*(sqrt 2)^2, or pi*2, or 2pi.
Add the area of the triangle to this area of the semicircle (2pi) to find the total area of the figure.
Hint: the area of a triangle is (bh)/2, where h is the height, b is the base.
Answer:
-9/28
Step-by-step explanation:
<u>Step 1: Solve</u>
-6/7 * 3/8
-18/56
-18/2 / 56/2
<em>-9/28</em>
<em />
Answer: -9/28
The awnser is B. There Is no soulution reigon.
Hope It Helps (^_^) (O_O)
