Answer:
Explanation:
public static int cupsToOunces (int cups) {
int ounces = cups * 8;
return ounces;
}
This is a very simple Java method that takes in the number of cups in the recipe as a parameter, converts it to ounces, and then returns the number of ounces. It is very simple since 1 cup is equal to 8 ounces, therefore it simply takes the cups and multiplies it by 8 and saves that value in an int variable called ounces.
Answer:
public class array{
public static void main(String []args){
int[] array = {2,4,7,1,9};
int num_vals = array.length;
for(int i=0;i<num_vals;i++){
System.out.println(array[i] + " ");
}
for(int i=num_vals-1;i>=0;i--){
System.out.println(array[i] + " ");
}
}
}
Explanation:
First create the class in the java programming.
Then create the main function and declare the array with values.
Store the size of array in num_vals variable by using the function array.length.
create a for loop to iterate the each element in the array and then print on the screen with spaces and newline.
it traverse the loop from first to last.
Then, again create the for loop to iterate the each element in the array and then print on the screen with spaces and newline but the traversing start from last to first.
Answer:
Click Page Number, Click Current Position, Click Plain Number 1.
Explanation:
Just did it, e2020
Answer:
// here is code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int n,no_open=0;
cout<<"enter the number of lockers:";
// read the number of lockers
cin>>n;
// initialize all lockers with 0, 0 for locked and 1 for open
int lock[n]={};
// toggle the locks
// in each pass toggle every ith lock
// if open close it and vice versa
for(int i=1;i<=n;i++)
{
for(int a=0;a<n;a++)
{
if((a+1)%i==0)
{
if(lock[a]==0)
lock[a]=1;
else if(lock[a]==1)
lock[a]=0;
}
}
}
cout<<"After last pass status of all locks:"<<endl;
// print the status of all locks
for(int x=0;x<n;x++)
{
if(lock[x]==0)
{
cout<<"lock "<<x+1<<" is close."<<endl;
}
else if(lock[x]==1)
{
cout<<"lock "<<x+1<<" is open."<<endl;
// count the open locks
no_open++;
}
}
// print the open locks
cout<<"total open locks are :"<<no_open<<endl;
return 0;
}
Explanation:
First read the number of lockers from user.Create an array of size n, and make all the locks closed.Then run a for loop to toggle locks.In pass i, toggle every ith lock.If lock is open then close it and vice versa.After the last pass print the status of each lock and print count of open locks.
Output:
enter the number of lockers:9
After last pass status of all locks:
lock 1 is open.
lock 2 is close.
lock 3 is close.
lock 4 is open.
lock 5 is close.
lock 6 is close.
lock 7 is close.
lock 8 is close.
lock 9 is open.
total open locks are :3
Answer:
a) EDI Semantic Layer
Explanation:
EDI is an acronym for electronic data interchange and it can be defined as a form of communication between interconnected computer systems and software applications with respect to business informations in standard digital formats.
This ultimately implies that, electronic data interchange (EDI) involves the transfer of business informations such as financial transactions between the computer systems of various organizations such as banks, companies, governmental agencies, etc. Thus, it avails businesses the ability to create strategic communications using computer to computer links to effectively and efficiently exchange business informations electronically or in digital formats.
Hence, the EDI Semantic layer describes the business application that is driving electronic data interchange (EDI).
