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myrzilka [38]
2 years ago
10

Help me please . . . . . . . . . . . . . Thanks

Mathematics
1 answer:
IceJOKER [234]2 years ago
5 0
I believe the answer is -1
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Answers is 1000 in. Hope this helped
6 0
3 years ago
Donata bought 4 lemons and 4 plums at the local supermarket for a total of $ 21.60. Dan bought 11 lemons and 6 plums at the same
VashaNatasha [74]
  1. you must establish a equation system  with the information given , 4x numbers of limon , where x represent the cost of every lemon and 4y numbers of plums , where y represents the cost of plums
  2. now  the equation system is 1) 4x+ 4y = 21,60 and 2) 11x+ 6y = 40.29
  3. of the equation 1 you must obtain the value of x, 4x = 21.60+4y ⇒x=21.60/4+4y/4⇒x= 5.4+y
  4. now with the value of x , it is substitute in the equation 2)   11(5.4+y) + 6y = 40.29 , ⇒ 59.4 + 11y + 6y = 40.29 ⇒  17y = 40.29-59.4⇒ y = -19,11/7⇒ y = -2.73
  5. the value of y is substitute in the equation 1) x = 5.4 + ( -2,73)⇒ x= 2,67,  where ,the price of every lemon is $ 2,67
6 0
3 years ago
Minnesota Public Radio wants to duplicate a survey conducted in 2016 that found that 65% of adults living in Minnesota felt that
vesna_86 [32]

Answer:

The number of people needed  is n =684  

Step-by-step explanation:

From the question we are told that

  The population proportion is  p = 0.65

   The margin of error is  E = 0.03

From the question we are told the confidence level is  90% , hence the level of significance is    

      \alpha = (100 - 90 ) \%

=>   \alpha = 0.10

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.645

Generally the sample size is mathematically represented as

       n =[ \frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * p(1-p)

=>    n =[ \frac{1.645 }{0.03} ]^2 * 0.65(1-0.65)

=>    n =684  

6 0
3 years ago
Through:(3,-1),slope=-1
Wewaii [24]

Answer:

y = -x + 2

Step-by-step explanation:

Use the point-slope formula y - k = m(x -h):

y - [-1] = -1(x - 3), or

y + 1 = -x + 3, or

y = -x + 2

5 0
3 years ago
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