Determining Whether a Point Lies on a Circle

Mathematics

2 answers:

Softa [21]3 years ago

6 0

Answer:

Step-by-step explanation:

If the center is at (0, 0) and if (0, -9) lies on the circle, then the radius must be 9.

In this case, the equation of this circle is

x^2 + y^2 = r^2 = 9^2.

Does (8, 717) satisfy this equation? No. 717^2 would be far outside of the circle. the distance from the center to the point (8, 17) is not the same as the radius

Ket [755]3 years ago

6 0

Answer:

Yes, the distance from the origin to the point

(8, ) is 9 units.

Step-by-step explanation:

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castortr0y [4]

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3 years ago

Which expression simplifies...

Zina [86]

Answer:

see below

Step-by-step explanation:

If suffices to look at the last term. It must simplify to 4/(3w²), so the exponents of z must match in numerator and denominator, and the ratio of constants must reduce to 4/3.

The exponents of z have the right values in choices B and D, but the ratio of constants only matches in choice D. Looking at the rest of choice D, we see that we can factor 6w²z² from both numerator and denominator, then factor 2 from the remaining numerator to make it match the desired form.

$\dfrac{(12w^2z^4-24w^2z^2)}{18w^4z^2}=\dfrac{6w^2z^2}{6w^2z^2}\cdot\dfrac{2z^2-4}{3w^2}=\dfrac{2(z^2-2)}{3w^2}$