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Setler79 [48]
3 years ago
9

System w/Elimination-2x-9y=-25-4x-9y=-25

Mathematics
1 answer:
Lerok [7]3 years ago
5 0

x=0 and y=\frac{25}{9}

Step-by-step explanation:

We need to solve the system by elimination and find values of x and y

-2x-9y=-25\,\,\,(1)\\-4x-9y=-25\,\,\,(2)

Subtract eq(1) and eq(2)

-2x-9y=-25\,\,\,(1)\\-4x-9y=-25\,\,\,(2)\\+\,\,\,+\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,+\\---------\\2x=0\\x=0

Now Multiply equation (1) by 2 and subtract with eq(2)

-4x-18y=-50\\-4x-9y=-25\\+\,\,\,\,\,\,+\,\,\,\,\,\,\,\,\,\,\,\,\,\,+\\--------\\-9y=-25\\y=\frac{-25}{-9}\\y=\frac{25}{9}

So, x=0 and y=\frac{25}{9}

Keywords: system by elimination

Learn more about system by elimination at:

  • brainly.com/question/6075514
  • brainly.com/question/2115716
  • brainly.com/question/4192226

#learnwithBrainly

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16x^2-36

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8.) A line passes through the points (k, 4) and (3, -6). The line is perpendicular to
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Answer:

K = 43

Step-by-step explanation:

We'll begin by determining the gradient of the equation 5y + 4x = 8. This can be obtained as follow:

5y + 4x = 8

Rearrange

5y = 8 – 4x

5y = –4x + 8

Comparing 5y = –4x + 8 with y = mx + c, the gradient m is –4

Next, we shall determine the gradient of the line perpendicular to the line with equation 5y = 8 – 4x.

This can be obtained as follow:

For perpendicular lines, their gradient is given by:

m1 × m2 = – 1

With the above formula, we can obtain the gradient of the line as follow:

m1 × m2 = – 1

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Divide both side by –4

m2 = –1/–4

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Finally, we shall determine the value of k as follow:

Coordinate => (k, 4) and (3, –6)

x1 coordinate = k

y1 coordinate = 4

x2 coordinate = 3

y2 coordinate = –6

Gradient (m) = 1/4

m = (y2 – y1) / (x2 – x1)

1/4 = (–6 – 4) / (3 – K)

1/4 = –10 /(3 – K)

Cross multiply

3 – K = 4 × –10

3 – K = –40

Collect like terms

– K = – 40 –3

–k = –43

Divide both side by – 1

K = –43/–1

k = 43

3 0
3 years ago
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