Answer:
Below
Step-by-step explanation:
All figures are squares. The area of a square is the side times itself
Let A be the area of the big square and A' the area of the small one in all the 5 exercices
51)
● (a) = A - A'
A = c^2 and A' = d^2
● (a) = c^2 - d^2
We can express this expression as a product.
● (b) = (c-d) (c+d)
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52)
● (a) = A-A'
A = (2x)^2 = 4x^2 and A'= y^2
● (a) = 4x^2 - y^2
● (b) = (2x-y) ( 2x+y)
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53)
● (a) = A-A'
A = x^2 and A' = y^2
● (a) = x^2-y^2
● (b) = (x+y) (x-y)
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54)
● (a) = A-A'
A = (5a)^2 = 25a^2 and A' =(2b)^2= 4b^2
● (a) = 25a^2 - 4b^2
● (a) = (5a-2b) (5a+2b)
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55)
● (a) = A - 4A'
A = (3x)^2 = 9x^2 and A'= (2y)^2 = 4y^2
● (a) = 9x^2 - 4 × 4y^2
● (a) = 9x^2 - 16y^2
● (a) = (3x - 4y) (3x + 4y)
We only need the percent
straberry:banana=2:3
2+3=5
banana=3 units
3/5=0.60=60%
60% is banana
and also 18cups is banana
<h2>
Answer with explanation:</h2>
The average rate of change for function f(x) over the interval a ≤ x ≤ b is given by :-
So, the rate of change for function 
over the interval −3 ≤ x ≤ 4 :
The rate of change for function 
over the interval −3 ≤ x ≤ 4 :
So, the rate of change for g(x) is greater than f(x) over the interval −3 ≤ x ≤ 4.
Your domain is all positive numbers, and your range is all numbers. this is because no matter what you plug in for y, x will only ever get extremely close to 0, but never reach it or go below it, and if you put in large values of y x will get very big.
