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vova2212 [387]
3 years ago
10

Pls help i will give brainliest​

Mathematics
1 answer:
AlexFokin [52]3 years ago
8 0

Answer:

4:120, 6:180, 8:240

each time it's 30 x the amount of bags, it's 30 pounds a bag

Step-by-step explanation:

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Factor 125x^3-1000. Show your work.
Salsk061 [2.6K]

The left term is (5x)³.

The right term is 10³.

So, you can use the formula for the factorization of the difference of cubes.

... a³ - b³ = (a-b)(a² +ab +b²)

Here, you have a=5x, b=10, so the factorization is

... 125x³ -1000 = (5x-10)(25x² +50x +100)

4 0
3 years ago
Plz help ASAP I need to find the slope of the line
dmitriy555 [2]
Use formula y2-y1 over x2 - x1

3-0/4-0

3/4 is ur answer
3 0
4 years ago
Read 2 more answers
Find a and b if the point p(6,0) and Q(3,2) lie on the graph of ax+ by=12
tiny-mole [99]

to get the equation of any straight line we only need two points off of it, hmmm let's use P and Q here and then let's set the equation in standard form, that is

standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

(\stackrel{x_1}{6}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{6}}}\implies \cfrac{2}{-3}\implies -\cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{2}{3}}(x-\stackrel{x_1}{6})

\stackrel{\textit{multiplying both sides by }\stackrel{LCD}{3}}{3(y-0)~~ = ~~3\left( -\cfrac{2}{3}(x-6) \right)}\implies 3y=-2(x-6) \\\\\\ 3y=-2x+12 \implies \stackrel{a}{2} x+\stackrel{b}{3} y=12

5 0
2 years ago
Please help I really need it
zavuch27 [327]
Its when x+-1 because thats when f of x or f(x) is highest
4 0
4 years ago
I need help on doing this problem
Mamont248 [21]

<em>Hey</em><em> </em><em>mate</em><em> </em><em>!</em><em>!</em><em> </em>

Step-by-step explanation:

[ Refer to the attachment ]

8 0
3 years ago
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