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3 years ago

In trapezoid ABCE, AB||CD. If the mZA 62° determine the m2D

Mathematics

2 answers:

motikmotik3 years ago

8 0

The answer is 53 to the power of 6

Ede4ka [16]3 years ago

3 0

53 to the power of 6

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Help find the next term

WINSTONCH [101]

It’s 4/3. The sequence is all multiplied by 1/3 so the 5th term is 12,6th is 4, and 7th is 4/3

7 0

3 years ago

One Friday night, two large groups of people called Weston Taxi Service. The first group requested 2 sedans and 1 minivan, which

muminat

Answer:

Sedan: 4 passengers

Minivan: 6 passengers

Step-by-step explanation:

We can write the following system of equations:

$\begin{cases}2s+1m=14 \\2s+2m=20\end{cases}$ , where $s$ represents the number of people a sedan can seat and $m$ represents the number of people a minivan can seat.

Subtracting the first equation from the second, we have:

$2s+2m-(2s+1m)=20-14,\\\\m=6$

Now plug in $m=6$ in any of the equations to solve for $s$ :

$2s+1(6)=14, \\2s=8, \\s=4$

Verify that the solution pair $(4, 6)$ works:

$2(4)+1(6)=14\: \checkmark \\2(4)+2(6)=20 \: \checkmark$

Therefore, a sedan can hold 4 passengers and a minivan can hold 6 passengers.

4 0

3 years ago

Graph and label the image of the figure below after a dilation by a factor of 1/2.

neonofarm [45]

Answer:

M' (1.5, -1), F' (2, -1), L' (0.5 -2.5), W' (2.5, -2.5)

see graph below

Explanation:

Given:

The image of a quadrilateral on a coordinate plane

To find:

The coordinates of the new image after dilation of 1/2 have been applied to the original image.

Then graph the coordinates

First, we need to state the coordinates of the original image:

M = (3, -2)

F = (4, -2)

L = (1, -5)

W = (5, -5)

Next, we will apply a scale factor of 1/2:

$\begin{gathered} Dilation\text{ rule:} \\ (x,\text{ y\rparen}\rightarrow(kx,\text{ ky\rparen} \\ where\text{ k = scale factor} \\ \\ scale\text{ factor = 1/2} \\ M^{\prime}\text{ = \lparen}\frac{1}{2}(3),\text{ }\frac{1}{2}(-2)) \\ M^{\prime}\text{ = \lparen}\frac{3}{2},\text{ -1\rparen} \\ \\ F\text{ = \lparen}\frac{1}{2}(4),\text{ }\frac{1}{2}(-2)) \\ F^{\prime}\text{ = \lparen2, -1\rparen} \end{gathered}$ $\begin{gathered} L\text{ = \lparen}\frac{1}{2}(1),\text{ }\frac{1}{2}(-5)) \\ L^{\prime}\text{ = \lparen}\frac{1}{2},\text{ }\frac{-5}{2}) \\ \\ W\text{ = \lparen}\frac{1}{2}(5),\text{ }\frac{1}{2}(-5)) \\ W^{\prime}\text{ = \lparen}\frac{5}{2},\text{ }\frac{-5}{2}) \end{gathered}$

The new coordinates:

M' (3/2, -1), F' (2, -1), L' (1/2, -5/2), W' (5/2, -5/2)

M' (1.5, -1), F' (2, -1), L' (0.5 -2.5), W' (2.5, -2.5)

Plotting the coordinates:

3 0

1 year ago

−3t≥39 What is the answer

Daniel [21]

Answer:

-3t ≥39

-3t/-3 ≥39/-3

t≤-13

3 0

3 years ago

Planet Mass (in grams) Jupiter 1.989 ∙ 10^30

Fiesta28 [93]

400 should be the answer. Hope this helps!

6 0

3 years ago