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marta [7]
2 years ago
11

Choose the three rectangular prisms that have a volume of 24 cm3. = 1 cm A. D. E.

Mathematics
1 answer:
OlgaM077 [116]2 years ago
8 0

Answer: I think is A, D, E

Step-by-step explanation:

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kherson [118]
The answer is <span>$11.43

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2 years ago
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Find the number of pairs (a,b) of integers such that<br> a+2/a+5=b/3
Viktor [21]

Answer:

  6

Step-by-step explanation:

The expression can be rearranged to ...

  b = 3 -9/(a+5)

In order for b to be an integer, (a+5) must be an integer divisor of 9. There are exactly 6 of those: ±1, ±3, ±9.

The attached table shows the values (a, b) = (x₁, f(x₁)).

3 0
3 years ago
If equal amounts are added to the numerator and the denominator of the current ratio, the ratio will always:
Marta_Voda [28]

Answer:

Increase?

Step-by-step explanation:

Because think about it let's use 1/2 as an example.

1/2 equals .5 now lets add 2 to both the numerator and denominator

3/4 is the result and it also equals .75 which is larger than .5 so that's why the answer is increase.

and u can keep on going on with the method

4/5=.8

7 0
3 years ago
What is the difference of the volumes of the two oblique pyramids, both of which have square bases? Round the volumes to the nea
ad-work [718]

Answer:

Step-by-step explanation:

See attachment for the figure

Volume of pyramid can be defined as

V = 1/3 x area of the base x height.

-> Pyramid A:

Volume of Pyramid can be determined by:

V = 1/3 x (2.6cm)² x (2cm) = 4.5067 cm³

Pyramid B:

Volume of Pyramid can be determined by:

V = 1/3 x (2cm)² x (2.5cm) =  3.3333 cm³

Difference b/w two oblique pyramids: 4.5067 cm³ - 3.333 cm³ = 1.17 cm³

By Rounding the volumes to the nearest tenth of a centimeter

1.17cm³ ≈ 1.2cm³

Therefore,  the difference of the volumes of the two oblique pyramids is 1.2cm³

4 0
3 years ago
Which is the simplified form of the expression ((p squared) (q Superscript 5 Baseline)) Superscript negative 4 Baseline times ((
Alexus [3.1K]

Answer:

q^{-30}

Step-by-step explanation:

Given the expression:

((p^2) (q ^5)) ^{-4} X ((p ^{-4}) (q^5)) ^{-2}

First, we open the outer brackets

=(p^{2X-4}) (q ^{5X-4})X (p ^{-4X-2}) (q^{5X-2})\\\\=(p^{-8}) (q ^{-20})X (p ^{8}) (q^{-10})\\\\$Next, we can collect like terms\\\\=p^{-8}Xp ^{8}Xq ^{-20}Xq ^{-10}\\\\$Applying addition law of indices\\\\=p^{-8+8}Xq^{-20+(-10)}\\\\=p^0 X q^{-30}\\\\=1 X q^{-30}\\\\=q^{-30}

Therefore:

((p^2) (q ^5)) ^{-4} X ((p ^{-4}) (q^5)) ^{-2}=q^{-30

8 0
3 years ago
Read 2 more answers
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