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3 years ago

In the equation 5b = 45, b = 10 True or False

Mathematics

2 answers:

professor190 [17]3 years ago

8 0

The answer is falseeeeeeeee

Reika [66]3 years ago

8 0

Answer:

False b=9

Step-by-step explanation:

In the equation 5b+45, b is equal to 9

The way we get this answer is by dividing each term by 5 and then simplifying

45/5

45/5=9

Hope this helps :)

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I don’t get this someone answer this for me please show all work

Paraphin [41]

Answer:

5x=2x−4−2

Subtract 2 from −4 to get −6.

5x=2x−6

Subtract 2x from both sides.

5x−2x=−6

Combine 5x and −2x to get 3x.

3x=−6

Divide both sides by 3.

x= -6/3

Divide −6 by 3 to get −2.

x=−2

Step-by-step explanation:

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3 years ago

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Answer:

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Step-by-step explanation:

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Please help! Graph the line for y+1=−3/5(x−4) on the coordinate plane. I just need help with the coordinates.

otez555 [7]

Answer:

SLOPE: - 3/5

Y-INTERCEPT: 7/5

Step-by-step explanation: Check picture :)

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4 years ago

write a function g whose graph represents a translation 2 units to the right followed by a horizontal stretch by a factor or 2 o

Alenkinab [10]

$\bf f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}\\\\
f(x)=&{{ A}} \left|{{ B }}x+{{ C}} \right|+{{ D}}
\\\\
--------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

with that template in mind, let's see,

$\bf f(x)=|x| \implies \begin{array}{lllccll}
f(x)=&1|&1x&+0|&+0\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}$

so, to shift it to the right by 2 units, simply set C = 2.
to stretch it by 2, set A = 1/2.

the smaller A is, the wider it opens, the larger it is, the more it shrinks.

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3 years ago

PLEASE HELP WILL MARK BRAINLIEST!!!!

podryga [215]

Last Choice is the answer

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2 years ago