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2 years ago

Which equation represents a line that passes through the two points in the table? y 3, 1 x6,6

Mathematics

1 answer:

egoroff_w [7]2 years ago

5 0

Answer:

the answer is 20. 46

and dont report me for this meme i give you ok

Step-by-step explanation:

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the numbers of girls in the choir is 4 times the number of boys in the choir .the total number of students is 60..how many girls

Inessa05 [86]

First, make up some variables to represent the number of Girls and Boys in the choir.

B = number of boys
G = number of girls

You know that there are 4 times as many girls in the choir as boys. Therefore, the equation you can write is:
$\frac{B}{G} = \frac{1}{4}$

If you cross-multiply, then you get the simplified equation:
G = 4B

Intuitively this makes sense since if you multiplied the number of boys in the class by 4, that would be equal to the number of girls you have.

Now, we know that the total class size is 60. So girls plus boys equals 60:
G+B = 60

To solve the equation, replace the G in this equation with the replacement you found before, 4B.
G + B = 60 -->
4B + B = 60 -->
5B = 60 -->
B = 12

However, you are trying to find the number of girls, so plug the answer back into your equation.
G + B = 60 -->
G + 12 = 60 -->
G + 12 -12 = 60 - 12 -->
G = 48

The number of girls you have is 48.

6 0

3 years ago

PLEASE HELP!! 25 POINTS !!! Graphing

Sunny_sXe [5.5K]

A = 6, 2
B = 3, 4
C = -10, 3
D = -4, 5
E = -5, -3
F = -4, -2
G = 3, -8

4 0

2 years ago

Read 2 more answers

F(x)=18x+11, find f(5)

Natalija [7]

Answer:

$\boxed {\tt f(5)=101}$

Step-by-step explanation:

We are given the function:

$f(x)=18x+11$

and asked to find f(5). Therefore, we must substitute 5 in for each $x$ .

$f(5)=18(5)+11$

Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition, Subtraction.

Multiply 18 and 5.

$f(5)=90+11$

Add 90 and 11.

$f(5)=101$

f(5) is equal to 101.

5 0

3 years ago

A manufacturer of Christmas light bulbs knows that 10% of these bulbs are defective. It is known that light bulbs are defective

Inessa05 [86]

Answer:

(a) P(X $\leq$ 20) = 0.9319

(b) Expected number of defective light bulbs = 15

Step-by-step explanation:

We are given that a manufacturer of Christmas light bulbs knows that 10% of these bulbs are defective. It is known that light bulbs are defective independently. A box of 150 bulbs is selected at random.

Firstly, the above situation can be represented through binomial distribution, i.e.;

$P(X=r) = \binom{n}{r} p^{r} (1-p)^{2} ;x=0,1,2,3,....$

where, n = number of samples taken = 150

r = number of success

p = probability of success which in our question is % of bulbs that

are defective, i.e. 10%

Now, we can't calculate the required probability using binomial distribution because here n is very large(n > 30), so we will convert this distribution into normal distribution using continuity correction.

So, Let X = No. of defective bulbs in a box

Mean of X, $\mu$ = $n \times p$ = $150 \times 0.10$ = 15

Standard deviation of X, $\sigma$ = $\sqrt{np(1-p)}$ = $\sqrt{150 \times 0.10 \times (1-0.10)}$ = 3.7

So, X ~ N( $\mu = 15, \sigma^{2} = 3.7^{2})$

Now, the z score probability distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

(a) Probability that this box will contain at most 20 defective light bulbs is given by = P(X $\leq$ 20) = P(X < 20.5) ---- using continuity correction

P(X < 20.5) = P( $\frac{X-\mu}{\sigma}$ < $\frac{20.5-15}{3.7}$ ) = P(Z < 1.49) = 0.9319

(b) Expected number of defective light bulbs found in such boxes, on average is given by = E(X) = $n \times p$ = $150 \times 0.10$ = 15.

5 0

3 years ago

ASAP helpppp I really need someone please

Pachacha [2.7K]

The answer for this is 6

7 0

3 years ago