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Maslowich
3 years ago
14

Please help due soon

Mathematics
1 answer:
Slav-nsk [51]3 years ago
7 0
I believe for this type of question you can plug in any number but this is my answer

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Is 0.963 close to 3/4
Alex777 [14]

There's no such concept as "close" in mathematics. Or at least, you have to specify when you consider two numbers to be "close".

All we can say is that, since 3/4=0.75, the two numbers are

0.963-0.75=0.213

units apart. Is this small enough to consider them as "close"? Is this big enough to consider them not to be "close"?

You should clarify more what you mean so that a definitive answer can be given.

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Y=2x+10 if I graphed correctly!
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there are 110 students on our team. 40% of the students dressed up for collage day. how many students on out team are wearing th
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A collector’s item is purchased for $150 and its value increases by 3% each year. Which graph can be used to determine approxima
VikaD [51]

we are given

A collector’s item is purchased for $150

so,

P=150

its value increases by 3% each year

so,

r=0.03

t is time in years

Let's assume cost of item after t years is C(t)

so, we can use formula

C(t)=P(1+r)^{t}

now, we can plug values

C(t)=150(1+0.03)^{t}

C(t)=150(1.03)^{t}

so, equation is

C(t)=150(1.03)^{t}

After doubling

C(t)=2*150=300

so, we can set C(t)=300

and then we can solve for t

300=150(1.03)^{t}

we get

t=23.44977

so, doubling time is 23.44977 years.........Answer

Graph:

we can draw graph of

C(t)=150(1.03)^{t}


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Answer:

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Step-by-step explanation:

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