Answer:
Miriam walks for 1.8 miles and jogs for 0.9 miles.
Step-by-step explanation:
The path for jogging is 2.7 miles.
One lap of the path, that is 2.7 miles, is completed by Miriam by jogging part and walking part.
Let the jogging part be x miles.
It is given she jogs half the distance she walks , therefore we can say that she walks for 2x miles.
So we can say that 2x + x = 2.7 miles ⇒ 3x = 2.7 miles
⇒ x = 0.9 miles.
Therefore Miriam walks for 1.8 miles and jogs for 0.9 miles.
Dh/dt = -32t + 24
-32t + 24 = 0 when maximum
32t = 24
t = 24/32
t = 3/4
To find the maximum height just substitute "t" in
h = -16 (9/16) + 24(3/4) + 7
h = -9 + 18 + 7
h = 16ft
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