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3 years ago

12

Rationalise the denominator

1 answer:

Margaret [11]3 years ago

8 0

Step-by-step explanation:

1. $\frac{2 \sqrt{3} }{ \sqrt{5} }$

multiply

$\sqrt{5}$

do both the numerator and denominater

$\frac{2 \sqrt{3} }{ \sqrt{5} } \times \frac{ \sqrt{5} }{ \sqrt{5} } = \frac{2 \sqrt{15} }{ \sqrt{25} } = \frac{2 \sqrt{15} }{5}$

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Please someone help me on this

mr_godi [17]

Answer:

the second one

Step-by-step explanation:

3 0

3 years ago

Suppose the distribution of home sales prices has mean k300, 000 and standard

777dan777 [17]

<u>Given</u>:

Mean,

$\mu = 300,000$

Standard deviation,

$\sigma = 50,000$

The Chebyshev theorem will be used for the solution of the given query,

i.e., $P(|X - \mu| < k \sigma ) \geq 1-\frac{1}{k^2}$

(i)

⇒ $1-\frac{1}{k^2} = 0.75$

$k = 2$

The lower limit will be:

= $\mu - k \sigma$

= $300000-2\times 50000$

= $200000$

The upper limit will be:

= $\mu + k \sigma$

= $300000+2\times 50000$

= $400000$

hence,

The 75% houses sold are between:

⇒ (200000, 400000)

(ii)

⇒ $\mu -k \sigma = Lower \ limit$

By putting the values, we get

$300000-50000k = 150000$

$300000-150000=50000k$

$150000=50000k$

$k=\frac{150000}{50000}$

$=3$

now,

⇒ $1-\frac{1}{k^2} = 1-\frac{1}{3^2}$

$=\frac{8}{9}$

$=0.8888$

$=88.88$ (%)

hence,

88.88% houses sold between 150000 and 450000.

(iii)

⇒ $\mu - k \sigma = Lower \ limit$

By putting the values, we get

$300000-50000k = 170000$

$300000-170000=50000 k$

$130000= 50000 k$

$k = \frac{130000}{50000}$

$=2.6$

now,

⇒ $1-\frac{1}{k^2} = 1-\frac{1}{2.6^2}$

$=0.8521$

$=85.21$ (%)

hence,

85.21% houses are sold between 170000 and 430000.

Learn more:

brainly.com/question/20897803

3 0

3 years ago

At 10:05 a.m., there are 2 microscopic bacteria cells in the bottle. At 10:15 a.m., there are 8 cells in the bottle.

damaskus [11]

Answer:

10:30 a.m

Step-by-step explanation:

just got it right on edeg

4 0

3 years ago

Read 2 more answers

(-10, -7), (-8, 1)<br> Distance between

liubo4ka [24]

Answer:9

Step-by-step explanation

√(x2-x1)^2 +(y2-y1)^2

√(-7-(-10)^2 +(1-(-8)^2

√(-7+10)^2 + (1+8)^2

√(3)^2 +(9)^2

√(9+81)

√90

=9.48

Approximately 9

7 0

4 years ago

Please solve this question?

Alchen [17]

Given,

$\lim_{x}^{a}\dfrac{x^{2/3}-a^{2/3}}{x-a}$

We can use L'Hopital's Rule to get,

$\lim_{x}^{a}\dfrac{2}{3-\sqrt[3]{x}}$

Now plug in a,

$\boxed{\dfrac{2}{3-\sqrt[3]{a}}}$

Hope this helps.

r3t40

3 0

4 years ago