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lys-0071 [83]
3 years ago
12

Which expression is equal to 728‾‾‾√−563‾‾‾√ ?

Mathematics
2 answers:
svet-max [94.6K]3 years ago
7 0
The answer is The 3rd one
marusya05 [52]3 years ago
7 0

Answer:

The correct option is 3.

Step-by-step explanation:

The given expression is

7\sqrt{28}-5\sqrt{63}

It can be written as

7\sqrt{4\times 7}-5\sqrt{9\times 7}

7\sqrt{2^2\times 7}-5\sqrt{3^2\times 7}

Using product property of radical expressions, we get

7(\sqrt{2^2}\times \sqrt{7})-5(\sqrt{3^2}\times \sqrt{7})               [\because \sqrt{ab}=\sqrt{a}\sqrt{b}]

7(2\times \sqrt{7})-5(3\times \sqrt{7})

14\sqrt{7}-15\sqrt{7}

Taking out common factors.

\sqrt{7}(14-15)

\sqrt{7}(-1)

-\sqrt{7}

Therefore the correct option is 3.

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The market is located at point (−4, −3) on the coordinate graph. The barber shop is 8 units to the right and 4 units up from the
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Answer:

(4, 1)

Step-by-step explanation:

8 units to the right = x + 8, so -4 + 8 = 4

4 units up = y + 4, so -3 + 4 = 1

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3 years ago
The letters for the word SCHOOL are placed in a hat. What is the probability of drawing the letter o out of the hat?
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Answer: 2/6 or 1/3

Step-by-step explanation:

SCHOOL has 6 letters in it and two O's. Therefore, it would be 2/6 or simplified it would be 1/3.

That was FUN!

8 0
3 years ago
How long does Ashley work on her sculpture?
Alex73 [517]
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4 0
3 years ago
$49.95 pair of shoes; 5% tax
Keith_Richards [23]

Answer:

$52.44

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega
AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is \frac{1}{3^8} is correct answer

Therefore [(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2

To find the simplified form of the given expression :

[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2

=(2^{-2})^{-3}(3^4)^{-3}\times (2^{-3})^2(3^2)^2 ( using the property (ab)^m=a^m.b^m )

=(2^6)(3^{-12})\times (2^{-6})(3^4) ( using the property (a^m)^n=a^{mn}

=(2^6)(2^{-6})(3^{-12})(3^4) ( combining the like powers )

=2^{6-6}3^{-12+4} ( using the property a^m.a^n=a^{m+n} )

=2^03^{-8}

=\frac{1}{3^8} ( using the property a^{-m}=\frac{1}{a^m} )

Therefore [(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}

Therefore option "StartFraction 1 Over 3 Superscript 8" is correct

That is \frac{1}{3^8} is correct answer

6 0
3 years ago
Read 2 more answers
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