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stiv31 [10]
3 years ago
9

Can y’all help me out please

Mathematics
1 answer:
Sliva [168]3 years ago
4 0

Answer:

D. the function approches 1 as x approches -∞ and ∞

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The weights of certain machine components are normally distributed with a mean of 8.04 g and a standard deviation of 0.08 g. Fin
NISA [10]

Answer:

The bottom 3 is separated by weight 7.8896 g and the top 3 is separated by weight 8.1904 g.

Step-by-step explanation:

We are given that

Mean, \mu=8.04 g

Standard deviation, \sigma=0.08g

We have to find the two weights that separate the top 3% and the bottom 3%.

Let x be the weight of  machine components

P(Xx_2)=0.03

P(X

=0.03

From z- table we get

P(Z1.88)=0.03

Therefore, we get

\frac{x_1-8.04}{0.08}=-1.88

x_1-8.04=-1.88\times 0.08

x_1=-1.88\times 0.08+8.04

x_1=7.8896

\frac{x_2-8.04}{0.08}=1.88

x_2=1.88\times 0.08+8.04

x_2=8.1904

Hence, the bottom 3 is separated by weight 7.8896 g and the top 3 is separated by weight 8.1904 g.

5 0
3 years ago
Solve and graph the absolute value inequality: |2x + 4| > 14
rewona [7]
It is very simple, <span>|2x + 4| > 14, we have 2x+4>14 or   -(2x+4) >14 (absolute value definition) so 2x> 14-4, x>10/2=5  or -2x>14+4, -x>18/2=9, implies x< - 9
the solution is x>5, or x< -9, so the answer is </span>number line with open circles on _9 and 5, shading going in the opposite directions.
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Step-by-step explanation:

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73x+y=-4 I hope it help you.
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