Answer:
Explanation:
<u>1) Calculate the volume of the water in the tank.</u>
- Area of the base of the tank: B = 7 ft × 4 ft = 28 ft²
- Height of the tank: H = 9 in = 9 in × 1 ft / 12 in = 0.75 ft
- Volume of the tank: V = area of the base × height = B × H = 28 ft² × 0.75 ft = 21 ft³.
<u>2) Calculate the weight of 21 ft³ of water.</u>
Since this is not a chemistry question but a math question, I will not use the fomula of density but set a proportion with one unknown:
- 62.4 lb / 1 ft³ = x / 21 ft³
Solve for x:
- x = 21 ft³ × 64 lb / ft³ = 1,310.4 lb.
So, rounding to the next integer, the water in the tank weighs 1,310 pounds, when it is full.
Answer: 23 degrees
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Explanation:
Using the inscribed angle theorem we can connect the central angle ABC and the inscribed angle ADC. The reason why is because they both cut off the minor arc AC
Angle ABC is given to be 46 degrees, the formula we use is shown below
central angle = 2*(inscribed angle)
angle ABC = 2*(angle ADC)
46 = 2*(angle ADC)
46/2 = 2*(angle ADC)/2 ... divide both sides by 2
23 = angle ADC
angle ADC = 23 degrees
The answer is O f(x) =-35x+5
9514 1404 393
Answer:
38
Step-by-step explanation:
The product of the given numbers is 38.4888. Rounding this to two significant digits gets you 38.
Answer: x+5 with a remainder of 3 (can also be said as 3/x-4)
Step-by-step explanation: See attachment
