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3 years ago

2. Are these triangles congruent?

Mathematics

1 answer:

snow_tiger [21]3 years ago

4 0

Answer:

Step-by-step explanation:

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What is 3 over 6 with a negative exponent of 1

kolbaska11 [484]

(3/6)^-1 negative exponent flips the fraction

(6/3)

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4 years ago

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Find each missing measure.

nikklg [1K]

I’m not sure about angle Q but angle R would be the same it would be 74 I’m pretty sure

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3 years ago

If 6 is added to three quarters of a certain number, the result is 42 . Find the original number

Basile [38]

Answer:

Step-by-step explanation

Hello!

3x/4 + 6=42

3x/4=42-6 = 36

3x = 36*4

3x = 144

x= 144/3 =48

3/4 of 48 = (48*3) / 4 =36

36+6=42

the original number is 48

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3 years ago

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Nutritionists recommend that people eat

mixer [17]

The amount of grams of fiber that Jodi should eat to meet the recommended daily amount of fiber is 12 grams.

<h3>How many more grams of fiber should Jodi eat?</h3>

The first step is to convert milligrams to grams.

1 milligram = 0.001 grams

25,000 x 0.001 = 25

Now subtract the recommended amount from the quantity eaten:

25 - (8 + 4 + 1 ) = 12 grams

Please find attached the complete question. To learn how to convert units, please check: brainly.com/question/25993533

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2 years ago

Which statement describes the inverse of m(x) = x^2 – 17x?

DochEvi [55]

Given:

The function is

$m(x)=x^2-17x$

To find:

The inverse of the given function.

Solution:

We have,

$m(x)=x^2-17x$

Substitute m(x)=y.

$y=x^2-17x$

Interchange x and y.

$x=y^2-17y$

Add square of half of coefficient of y , i.e., $\left(\dfrac{-17}{2}\right)^2$ on both sides,

$x+\left(\dfrac{-17}{2}\right)^2=y^2-17y+\left(\dfrac{-17}{2}\right)^2$

$x+\left(\dfrac{17}{2}\right)^2=y^2-17y+\left(\dfrac{17}{2}\right)^2$

$x+\left(\dfrac{17}{2}\right)^2=\left(y-\dfrac{17}{2}\right)^2$ $[\because (a-b)^2=a^2-2ab+b^2]$

Taking square root on both sides.

$\sqrt{x+\left(\dfrac{17}{2}\right)^2}=y-\dfrac{17}{2}$

Add $\dfrac{17}{2}$ on both sides.

$\sqrt{x+\left(\dfrac{17}{2}\right)^2}+\dfrac{17}{2}=y$

Substitute $y=m^{-1}(x)$ .

$m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}$

We know that, negative term inside the root is not real number. So,

$x+\left(\dfrac{17}{2}\right)^2\geq 0$

$x\geq -\left(\dfrac{17}{2}\right)^2$

Therefore, the restricted domain is $x\geq -\left(\dfrac{17}{2}\right)^2$ and the inverse function is $m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}$ .

Hence, option D is correct.

Note: In all the options square of $\dfrac{17}{2}$ is missing in restricted domain.

7 0

3 years ago