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Jlenok [28]
3 years ago
15

2. Are these triangles congruent?

Mathematics
1 answer:
snow_tiger [21]3 years ago
4 0

Answer:

D

Step-by-step explanation:

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A person places $6520 in an investment account earning an annual rate of 2.5%, compounded continuously. Using the formula V = Pe
beks73 [17]

Answer:

The amount of money, to the nearest cent, in the account after 3 years will be $ 7028.56

Step-by-step explanation:

The amount is given by

V = Pe^{rt}

Given P = $6520

r = 2.5%

t = 3 years

Substituting the given values, we get -

V = 6520 * e^{2.5*3/100 }\\V = 6520 * 1.078\\V = 7028.56

The amount of money, to the nearest cent, in the account after 3 years will be $ 7028.56

5 0
3 years ago
1/2x-20-x = 3(2x - 1) - (2x - 1)
yarga [219]

Answer:

x = -4

Step-by-step explanation:

1/2x - 20 - x = 6x -3 -2x +1

-1/2x -20 = 4x -2

-1/2x -4x = -2 +20

-9/2x = 18

9/2x = -18

9x = -36

x = -4

Give brainliest please!

hope this helps :)

5 0
2 years ago
Round 38.7 too ok the nearest whole. Use place value understanding and a number line to show your thinking
kobusy [5.1K]

Answer:

39

Step-by-step explanation:

so you look at decimal and if it is 5 or above you round up 1 and if it is 4 or below it stays the same

6 0
3 years ago
Read 2 more answers
Please help me answer one of these!
babunello [35]

This seems to be referring to a particular construction of the perpendicular bisector of a segment which is not shown. Typically we set our compass needle on one endpoint of the segment and compass pencil on the other and draw the circle, and then swap endpoints and draw the other circle, then the line through the intersections of the circles is the perpendicular bisector.


There aren't any parallel lines involved in the above described construction, so I'll skip the first one.


2. Why do the circles have to be congruent ...


The perpendicular bisector is the set of points equidistant from the two endpoints of the segment. Constructing two circles of the same radius, centered on each endpoint, guarantees that the places they meet will be the same distance from both endpoints. If the radii were different the meets wouldn't be equidistant from the endpoints so wouldn't be on the perpendicular bisector.


3. ... circles of different sizes ...


[We just answered that. Let's do it again.]


Let's say we have a circle centered on each endpoint with different radii. Any point where the two circles meet will then be a different distance from one endpoint of the segment than from the other. Since the perpendicular bisector is the points that are the same distance from each endpoint, the intersection of circles with different radii isn't on it.


4. ... construct the perpendicular bisector ... a different way?


Maybe what I first described is different; there are no parallel lines.



8 0
4 years ago
A square has a side length of 6 inches. It is enlarged and the new side length is 18 inches. What is the scale factor?​
vichka [17]
The scale factor is 3 because it’s going from 6 to 18, 18/6=3
5 0
3 years ago
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