Answer:
Hence after 3.98 sec i.e 4 sec Object will hit the ground .
Step-by-step explanation:
Given:
Height= 6 feet
Angle =28 degrees.
V=133 ft/sec
To Find:
Time in seconds after which it will hit the ground?
Solution:
<em>This problem is related to projectile motion for objec</em>t
First calculate the Range for object and it is given by ,
(2Ф)/
Here R= range g= acceleration due to gravity =9.8 m/sec^2
1m =3.2 feet
So 9.8 m, equals to 9.8 *3.2=31.36 ft
So g=31.36 ft/sec^2. and 2Ф=2(28)=56


fts
Now using Formula for time and range as

Vx is horizontal velocity
Ф
(28)
ft/sec
So above equation becomes as ,


T is approximately equals to 4 sec.
Answer:
Answer Placeholder (I'm going to solve it and answer when I'm done)
Step-by-step explanation:
I think that the answer is c
Answer:
Area = 1.54
Step-by-step explanation:
Area = π
π = 3.14
diameter = 1.4
radius (half of diameter) = 0.7
Area = 3.14 x 
Area = 3.14 x 0.49
Area = 1.5386
round to the nearest hundredth:
1.5386 = 1.54