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Alex
3 years ago
11

I need help with numbers 11 through 14 please if I don’t pass this I fail the class!!

Mathematics
1 answer:
gtnhenbr [62]3 years ago
4 0

Answer:

I hope you have options. and if you can find these answers in the options it will be good. cos I'm not so sure

11. 9

12. 8.6 or 9 approximately

13. 56 degree

14. 33 degree

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Bank a charges a $35 monthly fee for a checking account debit card with the limited train fashion bank b charges a $15 monthly f
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Total charges from bank A exists $15.

Total charges on Bank B spending exists $45.

<h3>How to estimate the Total charges on bank B?</h3>

Given: Bank A charges a $15 monthly fee for a checking account and debit card, with unlimited transactions.

Shade 25 transactions.

Total charges from bank A = $15 monthly

Bank B charged a $35 monthly fee for a checking account and debit card, plus $ 0.70 for each transaction.

She made 25 transactions.

Total charges on bank B = $35 + (0.40)25

Total charges on bank B = $35+10

Total charges on bank B = $45

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2 years ago
which of the following best describes the two radical expressions below? square root of 3 and square root of 2 A) they are equal
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D

Step-by-step explanation:

they are like terms

4 0
3 years ago
Can someone plzzz help with this ill give a pizza :((
nydimaria [60]

22 \times 18 = (20 + 2)(20 - 2) =  {20}^{2}  -  {2}^{2}  = 396

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3 years ago
Graph the system below and write its solution.
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2 years ago
In a G.P., the third term exceeds the first term by 16.
Tresset [83]

Answer:

Step-by-step explanation:

In a G.P, the nth term is given as

Un=ar^(n-1)

Where

a is first term

n is nth term

And r is common ratio

So in the question given above,

The third term exceed the first term by 16

i.e U3=U1+16

Where U1=a. First term

U3=a+16

Given also that, the sum if the third term and fourth term is 72.

Then U3+U4=72.

We are told to find common ratio (r)

U3=ar^3-1

U3=ar^2

Also, U4=ar^3

U3+U4=72

ar^2+ar^3=72

ar^2(1+r)=72. equation 1

Also for

U3=a+16

ar^2=a+16

ar^2-a=16

a(r^2-1)=16. From (x^2-y^2)=(x+y)(x-y)

Then,

a(r-1)(r+1)=16. Equation 2

Divide equation 2 by equation 1

a(r-1)(r+1)/ar^2(1+r) =16/72

Then a cancel a and (1+r) cancel (1+r)

So,

(r-1)/r^2=2/9

Cross multiply

9(r-1)=2r^2

2r^2-9r+9=0

Solving the quadratic equation

2r^2-6r-3r+9=0

2r(r-3)-3(r-3)=0

(r-3)(2r-3)=0

r-3=0. Or. 2r-3= 0

Then r=3 or r=3/2

8 0
3 years ago
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