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baherus [9]
3 years ago
8

HELP ME PLZ WILL MARK U AS BRAINLIEST

Mathematics
1 answer:
Contact [7]3 years ago
8 0

Answer:

1.33

Step-by-step explanation:

so mean is the average

so what you have to do is add the numbers for each person and then divide by the amount of numbers present. the question is asking for the difference so subtract the numbers for each from person.

mia's mean= 34.33

sophia's mean= 35.667

sophia-mia= 1.33

(check my work, and if you need help just comment)

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liubo4ka [24]
5k in 22, cause that’s a fast time
8 0
3 years ago
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Find the x in the following triangle <br> I’ll give brainliest
densk [106]

Answer:

78

Step-by-step explanation:

6 0
3 years ago
Please help me, I’ve been stuck on this question for a long time.
icang [17]

Answer:

1/64

Step-by-step explanation:

There are 8 equal sections

P(1) = 1/8  since there is one section with a 1 out of the 8 sections

Then we spin again

P(2) = 1/8 since there is one section with a 2 out of the 8 sections

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6 0
3 years ago
It is believed that students who begin studying for final exams a week before the test score differently than students who wait
olga55 [171]

Answer:

H0 : μ1 = μ2

H0 : μ1 < μ2

Step-by-step explanation:

Given :

Early studiers, group 1, mean μ1

Late studiers, group 2 ; mean, μ2

To test the claim that students who study earlier have an average score that is less than the average score for students

The null hypothesis ; there is no difference in average score

H0 : μ1 = μ2

Alternative hypothesis is early studiers means is less than average score of late studiers

H0 : μ1 < μ2

7 0
4 years ago
Solve the quadratic equation. Show all of your steps. x 2 + 3 x − 5 = 0
AlladinOne [14]

For this case we have the following quadratic equation:

x ^ 2 + 3x-5 = 0

Where:

a = 1\\b = 3\\c = -5

We look for the solution using the following formula:

x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}

Substituting the values:

x = \frac {-3 \pm \sqrt {3 ^ 2-4 (1) (- 5)}} {2 (1)}\\x = \frac {-3 \pm \sqrt {9 + 20}} {2}\\x = \frac {-3 \pm \sqrt {29}} {2}

Thus, we have two roots:

x_ {1} = \frac {-3+ \sqrt {29}} {2}\\x_ {2} = \frac {-3- \sqrt {29}} {2}

Answer:

x_ {1} = \frac {-3+ \sqrt {29}} {2}\\x_ {2} = \frac {-3- \sqrt {29}} {2}

3 0
3 years ago
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