Kudos if you can answer this.

Mathematics

1 answer:

Nataly_w [17]2 years ago

6 0

Answer:

X < 7/2

Step-by-step explanation:

Move the variable to the left, separate into possible cases , solve, find the intersections, find the union, and then you get your solution.

You might be interested in

Identify the quadratic term in the function, f(x)=2x^2-3x+5

Nadusha1986 [10]

Answer: 2x^2

The three terms are
2x^2
-3x
5
as they are separated by a plus sign. You can think of it as 2x^2 + (-3x) + 5 if you want. The quadratic term is the term with the exponent of 2

7 0

3 years ago

X^2+y^2=169, 3x+2y=39 please answer using substitution and each step

Oksanka [162]

Answer:

x=13,y=0

Step-by-step explanation:

We are given a system of equations

${x}^{2} + {y}^{2} = 169 - - eqn \: 1 \\ 3x + 2y = 39 - - eqn \: 2$

For equation 1,square all terms to reduce it

√x²+√y²=169

x+y=13

Make x the subject as required by the question to use substitution method

x=13-y

Plug x=13-y into eqn 2

3(13-y)+2y=39

39-3y+2y=39

39-y=39

y=39-39=0

Plug y=0 into equation 1

x+0=13

x=0

7 0

2 years ago

The height H of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 9

mariarad [96]

Answer:

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

Step-by-step explanation:

Statement is incorrect. Correct form is presented below:

The height $h(t)$ of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation $h(t) = 3 +90\cdot t -16\cdot t^{2}$ , where $t$ is time in seconds. After how many seconds will the ball be 84 feet above the ground.

We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:

$3+90\cdot t -16\cdot t^{2} = 84$