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labwork [276]
3 years ago
11

Every computer that a business owner purchases will lose most of its value after 5 years of use. the owner plans to purchase a c

omputer for $2.100 and replace it after 4 years.
The business owner bought a computer that cost $2,400 instead of $2,100. the owner plans to replace the computer after 3 years instead of 4 years. Comparing both methods, which statement is true about the remaining value of this computer after 3 years of use ?
Mathematics
1 answer:
pickupchik [31]3 years ago
5 0

Answer:

Step-by-step explanation:

a) Data and Calculations:

Estimated useful life of a computer = 5 years

Cost of a computer purchased = $2,400

Annual depreciation expense = $480 ($2,400/5)

This means that the business owner chooses to spread (expense) the cost of the computer over 5 years at a rate of $480.

After 3 years, the cost already expensed = $1,440 ($480 * 3)

The Remaining value of this computer after 3 years of use will be $960 ($2,400 - $1,440).

b) Depreciation is an accounting method for spreading (or expensing) the cost of a long-term asset over its useful life.

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Find all the prime factors of the three numbers. pick up the common factors, ONCE, then pick up the non-common factors one by one, multiply the factors, the product is the least common factor.
example: the least common multiple of 6, 8, and 15
6=2*3
8=2*2*2
15=3*5
Note: do not write 8 into 4*2, because 4 is not a prime number. you have to break the number down to prime factors only. 
Notice that 6 and 8 have a common factor 2, so pick up the 2;
 6 and 15 have a common factor of 3, so pick up the 3.
those are the only two shared factors, so 2×3
now pick up whatever is not shared:
the two 2s for 8 and the 5 for 15 is not shared, add 2, 2, and 5 to the multiplication: 2×3×2×2×5=120
120 is the least common multiples of 6,8, and 15

this is basically how it is done. I believe you can explain better in your own words. 

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Answer:

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