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DerKrebs [107]
3 years ago
15

The population of a bacterium doubles every hour. At 9 am, the population is 12 bacteria. The function P (t) = 12.2 models the b

acteria population t hours after 9 am What is the value of P (5) and what does it
represent in context?
A) The population is 120 bacteria at 2 pm
B)The population is 120 bacteria at 5 pm
C) The population is 384 bacteria at 2 pm
D) The population is 384 bacteria at 5p.m.
Mathematics
1 answer:
bagirrra123 [75]3 years ago
6 0

Answer: B

Step-by-step explanation:

The correct answer is B

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(y+6)^2-(y-2)^2 <br><br> I got 16y+26 but it is wrong?
Gemiola [76]

Answer:

16y + 32

Step-by-step explanation:

Expand each term.

(y+6)² - (y-2)²

= (y+6)(y+6) - (y-2)(y-2)

= y² + 12y + 36 - (y² - 4y + 4)

Subtract the second group by changing each term's signs

= y² + 12y + 36 - y² + 4y - 4

Collect like terms

= 16y + 32

5 0
3 years ago
F) Two numbers are in the ratio 5:4. If they differ by 12, what are the numbers?
Iteru [2.4K]

Answer:

First number = 60 and another number = 48

Step-by-step explanation:

Let two numbers are 5x and 4x.

The two number are differ by 12. We need to find the numbers.

ATQ,

5x-4x = 12

x = 12

Now first number = 5x

= 5(12)

= 60

Other number = 4x

= 4(12)

= 48

Hence, the numbers are 60 and 48.

8 0
3 years ago
at the craft store , alan bought a bag of orange and green marbles. the bag contained 25 marbles, and 40% of them where orange.
Kazeer [188]

Answer:

There are 10 orange marbles

Step-by-step explanation:

There are 25 marbles in the bag

40% are orange

To determine the number of orange marbles, we multiply the total number of marbles  by the percent that are orange

25 *40% = number of orange marbles

25*.40

10

There are 10 orange marbles


4 0
3 years ago
Read 2 more answers
Priya's cat weighs 5 1/2 pounds and her dog weighs 8 1/4 pounds.
Lilit [14]

Answer: The cat is 2/3 times as heavy as the dog.


Step-by-step explanation:

The weight of Priya's cat =5\frac{1}{2}\ pounds

Now, 5\frac{1}{2}=\frac{11}{2}\ pounds

The weight of her dog =8\frac{1}{4}\ pounds

8\frac{1}{4}=\frac{33}{4}\ pounds

Let cat is n times heavy as dog.

Then n=\text{cat's weight}\div\text{dog's weight}

n=\frac{{11}{2}\div\frac{33}{4}\\\Rightarrow\ n=\frac{11}{2}\times\frac{4}{33}\\\Rightarrow\ n=\frac{2}{3}

Hence, The cat is 2/3 times as heavy as the dog.

5 0
3 years ago
Read 2 more answers
Solve for the variable h.<br> f=12gh<br> h=?
s344n2d4d5 [400]
f=12gh\\\\12gh=f\ \ \ \ \ |divide\ both\ sides\ by\ 12g\\\\\boxed{h=\frac{f}{12g}}
4 0
3 years ago
Read 2 more answers
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