Because percentage is the numerator divided by the denominator of a fraction times one-hundred, we can set up this equation:
Now, we cross multiply.
Next, we divide both sides by 0.55 to get x by itself.
x = 60
So, 33 is 55% of 60.
Answer:
rod waves can give u the answer for that just play a some him
Answer:
1 3/7 quarts should be drained off and replaced with pure antifreeze.
1 3/7 ≈ 1.4286
Current amount of antifreeze in quarts is -
30/ 100 × 10 = 3
40% ---> 4 quarts
Let the amount drained of and replaced with antifreeze be x-
The amount left after draining off is 10 − x.
The amount of antifreeze is 30/ 100 (10−x).
30/100(10-x)+x=4
3-3/10x+x=4
3+x(1-3/10)=4
x=1*10/7=1 3/7 quarts
check;
10- 1 3/7 = 8 4/7
=(30/100*8 4/7)+1 3/7
=(3/10 * 60/7) + 10/7
=3*6/7 + 10/7
=28/7
=4
4 liters of pure antifreeze is mixed into 10 quarts.
<em>Answer: h = 120 ft; w = 80 ft </em>
<em></em>
<em>A = 9600 ft^2</em>
<em />
<em>Step-by-step explanation: Let h and w be the dimensions of the playground. The area is given by:</em>
<em></em>
<em>A = h*w (eq1)</em>
<em></em>
<em>The total amount of fence used is:</em>
<em></em>
<em>L = 2*h + 2*w + w (eq2) (an extra distance w beacuse of the division)</em>
<em></em>
<em>Solving for w:</em>
<em></em>
<em>w = L - 2/3*h = 480 - 2/3*h (eq3) Replacing this into the area eq:</em>
<em></em>
<em></em>
<em></em>
<em>We derive this and equal zero to find its maximum:</em>
<em></em>
<em> Solving for h:</em>
<em></em>
<em>h = 120 ft. Replacing this into eq3:</em>
<em></em>
<em>w = 80ft</em>
<em></em>
<em>Therefore the maximum area is:</em>
<em></em>
<em>A = 9600 ft^2</em>
<em />
