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irina1246 [14]
3 years ago
11

A)

Mathematics
1 answer:
lilavasa [31]3 years ago
3 0
Hi good afternoon!
I will help you today!
It’s when u plot the points it’s b
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Let​ T: set of real numbers R Superscript nℝnright arrow→set of real numbers R Superscript mℝm be a linear​ transformation, and
Klio2033 [76]

Answer:

\{T(v_1), T(v_2), T(v_3)\} is linearly dependent set.

Step-by-step explanation:

Given:  \{v_1,v_2,v_3\} is a linearly dependent set in set of real numbers R

To show: the set \{T(v_1), T(v_2), T(v_3)\} is linearly dependent.

Solution:

If \{v_1,v_2,v_3,...,v_n\} is a set of linearly dependent vectors then there exists atleast one k_i:i=1,2,3,...,n such that k_1v_1+k_2v_2+k_3v_3+...+k_nv_n=0

Consider k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0

A linear transformation T: U→V satisfies the following properties:

1. T(u_1+u_2)=T(u_1)+T(u_2)

2. T(au)=aT(u)

Here, u,u_1,u_2∈ U

As T is a linear transformation,

k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0\\T(k_1v_1)+T(k_2v_2)+T(k_3v_3)=0\\T(k_1v_1+k_2v_2+k_3v_3)=0\\

As \{v_1,v_2,v_3\} is a linearly dependent set,

k_1v_1+k_2v_2+k_3v_3=0 for some k_i\neq 0:i=1,2,3

So, for some k_i\neq 0:i=1,2,3

k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0

Therefore, set \{T(v_1), T(v_2), T(v_3)\} is linearly dependent.

6 0
3 years ago
Please help!!! Due today!!!<br> Will give brainliest
Flura [38]

Answer:poiujhygtfdoiuytoiuytrewqjhgfdsnbvcnbvnfhhghjgggggggggggggggggggggggggggggggggggggggggggggggggghhhhhhhhhhhhhhhhhhhkkkkkkguyumhjmk,l.uogtgbv mjbnh

Step-by-step explanation:

6 0
2 years ago
Leslie need 48 ounces of charcoal. How many pounds should she buy?
andreyandreev [35.5K]
16 ounces= 1 pound
48÷16=3
3 pounds
7 0
3 years ago
A translation of trapezoid PQRS (blue) to trapezoid P'Q'R'S' (green) is shown, where the location of Q' is the origin. The coord
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On USATestprep the answer is C) (c-a,-b)

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3 years ago
Cindy took a multiple choice test. The ratio of number of problems Cindy got incorrect to the number of problems she got correct
Nezavi [6.7K]

Answer:

42

Step-by-step explanation:

Divide 14/2 *6 to get your ratio.

Hope this helps!

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2 years ago
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