If angle 2=3x-6 solve for x

For the equation below, x is the input and y is the output. y = -4x 3 if the input is -8, then the output is .

Gnesinka [82]

From this we know that x = -8
So all we need to do is plug -8 into the equation everywhere there is an x

So y = -4 * -8 + 3

y = 32 + 3

So y is equal to 35, and since y is the output, the output is 35

3 0

3 years ago

Read 2 more answers

X^2-y^2=3y in polar form

Assoli18 [71]

Answer:

Step-by-step explanation:

put x=r cos θ

y=r sin θ

r²cos²θ-r²sin²θ=3rsin θ

r²(cos²θ -sin²θ)=3r sin θ

r²cos 2θ=3rsinθ

r cos 2θ=3 sin θ

r=3sec 2θ sin θ

5 0

3 years ago

The ground-state wave function for a particle confined to a one-dimensional box of length L is Ψ=(2/L)^1/2 Sin(πx/L). Suppose th

Hitman42 [59]

Answer:

(a) 4.98x10⁻⁵

(b) 7.89x10⁻⁶

(c) 1.89x10⁻⁴

(d) 0.5

(e) 2.9x10⁻²

Step-by-step explanation:

The probability (P) to find the particle is given by:

$P=\int_{x_{1}}^{x_{2}}(\Psi\cdot \Psi) dx = \int_{x_{1}}^{x_{2}} ((2/L)^{1/2} Sin(\pi x/L))^{2}dx$

$P = \int_{x_{1}}^{x_{2}} (2/L) Sin^{2}(\pi x/L)dx$ (1)

The solution of the intregral of equation (1) is:

$P=\frac{2}{L} [\frac{X}{2} - \frac{Sin(2\pi x/L)}{4\pi /L}]|_{x_{1}}^{x_{2}}$

(a) The probability to find the particle between x = 4.95 nm and 5.05 nm is:

$P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{4.95}^{5.05} = 4.98 \cdot 10^{-5}$

(b) The probability to find the particle between x = 1.95 nm and 2.05 nm is:

$P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{1.95}^{2.05} = 7.89 \cdot 10^{-6}$

(c) The probability to find the particle between x = 9.90 nm and 10.00 nm is:

$P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{9.90}^{10.00} = 1.89 \cdot 10^{-4}$

(d) The probability to find the particle in the right half of the box, that is to say, between x = 0 nm and 50 nm is:

$P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{0}^{50.00} = 0.5$

(e) The probability to find the particle in the central third of the box, that is to say, between x = 0 nm and 100/6 nm is:

$P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{0}^{16.7} = 2.9 \cdot 10^{-2}$

I hope it helps you!

3 0

4 years ago

Work out the volume of this prism.

aniked [119]

Answer:

Volume = 175 cm³

Step-by-step explanation:

We can picture this image as a whole rectangular prism, with a part that has been cut out of it.

Step 1: Volume of original prism

We are going to solve the volume of the original prism, with the dimensions of 9, 7, and 5

V = 9 * 7 * 5
V = 315

Step 2: Volume of part cut out

We are solving the volume of that part that has been cut out ( missing space)

V = 5 * (9-2) * (7-3)
V = 5 * 7 * 4
V = 140

Step 3: Total Volume

Now we just subtract the cutout part from the original volume

315 - 140
V = 175

Volume = 175 cm³

Note, we could have also found the volume by splitting this shape into two prisms with dimensions (9 * 3 * 5) and (4 * 5 * 2). This way would also get us:

V = (9 * 3 * 5) + (4 * 5 * 2)
V = 135 + 40
V = 175

-Chetan K

7 0

2 years ago

How many square feet of outdoor carpet will we need for this hole

DIA [1.3K]

Answer:

39ft²

Step-by-step explanation:

Divide up the Shape

Big rectangle:

a=lw

11*3=33ft

Small rectangle

2*3=6ft

Whole shape:

33+6=39ft²

4 0

3 years ago