M∠ADB + m∠BDC = m∠ADC [<span>angle addition postulate]
x + x + 10 = 60
2x + 10 = 60
2x = 60 - 10
2x = 50
x = 50/2
x = 25
a
m</span>∠ADB = x = 25°
b
m∠BDC = x + 10 = 25 + 10 = 35°
Answer:
2%
Step-by-step explanation:
Set up a proportion
x / 100 = 12 / 600
Cross multiply
600x = 1200
Divide both sides by 600
x = 2
I hope this helped and please mark me as brainliest!
Answer:
expression: (30/t) - 10
evaluation: 30/2 - 10 = 5
Step-by-step explanation:
17,16. That what comes next I think
Given: 3y cos x = x² + y²
Define

Then by implicit differentiation, obtain
3y' cos(x) - 3y sin(x) = 2x + 2y y'
y' [3 cos(x) - 2y] = 2x + 3y sinx)
Answer: