Question

3. Jaden received these two estimates from a moving company. Write and solve a

Answer 1

Answer:

Mileage = $71

Loading/Unloading Fee: -$980

Explanation:

The question has incomplete details. The complete question can be found online. The given parameters are:

Situation A

$Helpers = 6$

$Distance =95$

$Cost = 865$

Situation B

$Helpers = 5$

$Distance = 80$

$Cost = 780$

Solving (a): The equation.

Let

x = loading/unloading fee

y = mileage fee

For situation A, the equation will be:

$Cost = 6 * x + 95 * y$

$Cost = 6 x + 95y$

$6 x + 95y = 865$

For situation B, the equation will be:

$Cost = 5* x + 80*y$

$Cost = 5x + 80y$

$5x + 80y = 780$

So, the equations are:

$6 x + 95y = 865$

$5x + 80y = 780$

Solving (b): The solution

$6 x + 95y = 865$ --- (1)

$5x + 80y = 780$ --- (2)

Multiply (1) by 5 and multiply (2) by 6 to eliminate x

$5 * [$ $6 x + 95y = 865$$]$

$30x + 475y = 4325$

$6*[$$5x + 80y = 780$$]$

$30x + 480y = 4680$

Subtract the resulting equations

$30x - 30x + 475y - 480y = 4325 - 4680$

$-5y = -355$

Divide both sides by -5

$y = 71$

Substitute $y = 71$ in (1)

$6 x + 95y = 865$

$6x + 95 * 71 = 865$

$6x + 6745 = 865$

Collect like terms

$6x =- 6745 + 865$

$6x =-5880$

Divide both sides by 6

$x =-980$

The solution is correct but does not represent real life situation because x should be positive