You have been given an encrypted copy of the Final exam study guide here, but how do you decrypt and read it???

Convert the following hexadecimal numbers to decimal: (a) FF (b) F0A2 (c) 0F100 (d) 100

Hatshy [7]

Answer:

a) 255

b) 61602

c)

d)

Explanation:

You need to understand the decimal equivalent of hexadecimal numbers, from 0 to 9 numbers are represented the same way, from 10 to 15 we use the alphabet, meaning 10 equals A in hexadecimal base, 11-B, 12-C, 13-D, 14-E, and 15-F.

For your first exercise you'll enumerate the number's positions fromright to lef begining with 0:

a. F F

position 1 0

Now you'll multiply your hexadecimal number (using the decimal equivalent for your letters) for the base (16) elevated to the number of the position:

$F*16^{0}=15*1=15\\F*16^{1}=15*16=240$

Finally, you'll add your results:

240+15=255

FF=255

b. F 0 A 2

position 3 2 1 0

$2*16^{0}=2*1=2\\A*16^{1}=10*16=160\\0*16^{2}=0*256=0\\F*16^{3}=16*4096=61440\\\\2+160+0+61440=61602\\$

F0A2=61602

c. F 1 0 0

position 3 2 1 0

$0*16^{0}=0*1=0\\0*16^{1}=0*16=0\\1*16^{2}=1*256=256\\F*16^{3}=16*4096=61440\\0+0+256+61440=61696\\$

0F100=61696

d. 1 0 0

position 2 1 0

$0*16^{0}=0*1=0\\0*16^{1}=0*16=0\\1*16^{2}=1*256=256\\\\0+0+256=256\\$

100=256

I hope you find this information useful! Good luck!

8 0

3 years ago

Do the pros of interpersonal communication via social media outweigh the cons? Explain.

JulijaS [17]

Well in my opinion is that yes they do. The ability to be able to communicate with others so far way really helps society advance towards the future. And i cant stress of how the benefits of being able to share ideas with well anyone is so wonderful.

I hope this helps.

6 0

3 years ago

Read 2 more answers

You are given a class named Clock that has one int instance variable called hours.

Vlad [161]

Answer:

public Clock(int hours) {

this.hours = hours;

}

Explanation:

In Java programming language, Constructors are special methods that are called to initialize the variables of a class when a new object of the class is created with the new keyword. Consider the complete code for the class below;

public class Clock {

private int hours;

public Clock(int hours) {

this.hours = hours;

}

}

In this example above, an object of this class can created with this statement Clock myclock = new Clock(6); This is a call to the constructor and passes a parameter (6) for hours

7 0

3 years ago

Write a program to prepare the monthly charge account statement for a customer of CS CARD International, a credit card company.

WITCHER [35]

Answer:

import java.util.*;

import java.text.*;

class CreditCardBill

{

public static void main(String[] args)

{

Scanner sc = new Scanner(System.in);

NumberFormat defaultFormat = NumberFormat.getCurrencyInstance(Locale.US);

System.out.println("CS Card International Statement");

System.out.println("===============================");

System.out.print("Previous Balance: $");

double prevBalance = sc.nextDouble();

System.out.print("Additional Charges: $");

double addCharges = sc.nextDouble();

double interest;

if(prevBalance == 0)

interest = 0;

else

interest = (prevBalance + addCharges) * 0.02;

System.out.println("Interest: "+defaultFormat.format(interest));

double newBalance = prevBalance + addCharges + interest;

System.out.println("New Balance: "+defaultFormat.format(newBalance));

double minPayment;

if(newBalance < 50)

minPayment = newBalance;

else if(newBalance <= 300)

minPayment = 50.00;

else

minPayment = newBalance * 0.2;

System.out.println("Minimum Payment: "+defaultFormat.format(minPayment));

}

5 0

3 years ago

Implement a sublinear running time complexity recursive function in Java public static long exponentiation (long x, int n) to ca

Archy [21]

Answer:

Following are the code block in the Java Programming Language.

//define recursive function

public static long exponentiation(long x, int n) {

//check the integer variable is equal to the 0.

if (x == 0) {

//then, return 1

return 1;

}

//Otherwise, set else

else {

//set long data type variable

long q = exponentiation(x, n/2);

q *= q;

//check if the remainder is 1

if (n % 2 == 1) {

q *= x;

}

//return the variable

return q;

}

Explanation:

Following are the description of the code block.

Firstly, we define the long data type recursive function.
Then, set the if conditional statement and return the value 1.
Otherwise, set the long data type variable 'q' that sore the output of the recursive function.
Set the if conditional statement and check that the remainder is 1 and return the variable 'q'.

8 0

3 years ago