Answer:
D) radical 26
Step-by-step explanation:
So this is a question where you need to find the hypotenuse of a triangle
the sides are 1 and 5
you can use Pythagoras (a^2+b^2=c^2)
substitute the values in
1^2+5^2=c^2
simplify the exponents
1+25=c^2
add them together
26=c^2
take the square root of 26
the answer is radical 26
Answer:
y + 4 = 0(x + 5)
y + 4 = 0
y = -4
Step-by-step explanation:
Answer:
Given: △ABC, m∠B=90° AB=12, BC=16, BK ⊥ AC . Find: AC and BK.
Given: △ABC, m∠B=90°
Find: AC and BK.
Short leg 90 degrees Long leg Hypotenuse
AB=12 90 BC=16 AC= ?
AK = ? 90 BK = ? AB=12
AC = SQRT (AB*AB + BC*BC) = 20 [right triangle; Pythagorean Theorem]
Similar triangles:[Note: In diagram, share two angles. Therefore share three angles]
BK / 16 = AB / AC
BK / 16 = 12 / 20
BK = (3/5)16
BK = 48/5
another answer let see this
AB^2+BC^2=AC^2
12^2+16^2=AC^2
144+256=AC^2
400=AC^2
20=AC
# be careful#
Check the picture below, let's use those two points on the line to get its slope.
