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3 years ago

Help I don't understand

Mathematics

1 answer:

iren [92.7K]3 years ago

6 0

Since all the triangles = 180 you just have add the angles you do have together then subtract by 180. The missing side of trangle a =39 and the missing side of b is 79.6

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Mr. Kohl has a breaker containing n milliliters of solution to distribute to the students in his chemistry class. If he gives ea

77julia77 [94]

Answer:

There were 26 students in his class and the teacher had 83 ml of the solution.

Step-by-step explanation:

Mr. Kohl has a "x" amount of solution, if he divides it by the number of students "n" he'll give each student 3 milliliters and have a left over of 5 milliliters. If the amount of solution Mr. Kohl had was "x + 21" then he'd be able to give each student 4 milliliters of the solution. From these informations we have:

x = 3*n + 5

(x + 21)/n = 4

x + 21 = 4*n

x = 4*n - 21

Now that we have two equations and two variables we can solve the system of equations, as seen bellow:

3*n + 5 = 4*n - 21

3*n - 4*n = -21 - 5

-n = -26

n = 26

x = 4*26 - 21 = 83 ml

There were 26 students in his class and the teacher had 83 ml of the solution.

3 0

3 years ago

Math.............................................

emmasim [6.3K]

1. B) 3/2 = 1.5
2. B) 3/7

4 0

3 years ago

Read 2 more answers

Please answer as soon as possible. Due by 11:59

Basile [38]

15x+40=-47+27
15x+40=-20
15x=-60
X=-4

8 0

3 years ago

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An automobile dealer had 288 cars and trucks in stock during the month. He must pay an inventory fee of 52 per car and $5 per tr

Aleonysh [2.5K]

For the given conditions, we won’t get a practical solution.

<u>Solution:</u>

Given, An automobile dealer had 288 cars and trucks in stock during the month.

He must pay an inventory fee of 52 per car and $5 per truck.

He paid $849 for inventory foes.

We have to find how many cars and Trucks did he have during the month?

Now, let the number of trucks be n, then number of cars will be 288 – n

And, according to given information,

$\begin{array}{l}{5 \times n+52 \times(288-n)=849} \\\\ {\rightarrow 5 n+52 \times 288-52 n=849} \\\\ {\rightarrow 52 n-5 n=14976-849} \\\\ {\rightarrow 47 n=14127} \\\\ {\rightarrow n=300.57}\end{array}$

Here we got n > number of cars and trucks, which is practically impossible.

Hence, for the given conditions, we won’t get a practical solution

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3 years ago

Which shows 602 − 402 being evaluated using the difference of squares method?

Elden [556K]

The right answer for the question that is being asked and shown above is that: "602 − 402 = (3600 + 1600)(3600 − 1600) = 10,400,000" The equation that shows 602 − 402 being evaluated using the difference of squares method is that <span>602 − 402 = (3600 + 1600)(3600 − 1600) = 10,400,000</span>

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4 years ago

Read 2 more answers